The missing components in the table to the right are indicated with orange letters. Use the periodic table in the tools bar and

Answer:

The solution's absorbance measures 0.21168.

Explanation:

Provided that,

Wavelength = 500 nm

Molar absorptivity = 252 M⁻¹ cm⁻¹

Moles present = 0.00140

Total solution volume = 500.0 mL

Path length = 3.00 mm

We have to determine the molar concentration

Utilizing the formula for molar concentration

Where N = number of moles

V = volume

Input the values into the formula

Next, we will calculate the solution's absorbance

Using the absorbance formula

Substituting values into the equation

Therefore, the absorbance of the solution is 0.21168.

Answer: C. 151 g

Solution: The balanced equation given is:

From this equation, the ratio of moles between all substances is 1:1. We have 117 grams of LIOH and 141 grams of HBr available and need to calculate the theoretical yield of LiBr.

We should convert each reactant’s grams into moles to identify the limiting reagent since the theoretical yield relies on it.

Molar mass for LiOH = 6.94 + 15.999 + 1.008 = 23.947 grams per mole

Molar mass for HBr = 1.008 + 79.904 = 80.912 grams per mole

To find the moles of each reactant, we divide their grams by their respective molar masses.

Moles of LiOH = = 4.89 mol

Moles of HBr = = 1.74 mol

As there are fewer moles of HBr, it is the limiting reactant. With a 1:1 mol ratio between HBr and LiBr, 1.74 moles of LiBr can be produced.

Molar mass of LiBr = 6.94 + 79.904 = 86.844 grams per mole

The mass of LiBr formed = = 151 g LiBr

Based on calculations, the theoretical yield of LiBr is 151 g, hence the correct answer is C.

Answer:

Al (s) + AgClO3 (aq) will undergo a chemical reaction.

Al(s) + 3AgClO₃(aq) -----> Al(ClO₃)₃(aq) + 3Ag(s)

Cd(s) + CuNO3(aq) will also engage in a chemical reaction.

Cd(s) + 2CuNO₃ -----> Cd(NO₃)₂ + 2Cu

Explanation:

In chemical reactions, metal elements positioned lower in the activity series typically cannot replace those positioned higher in the series.

Metals located lower on the activity series are less likely to oxidize.

The activity series is referenced in this solution. (Note: While Cadmium is not directly illustrated, it falls between Iron (Fe) and Cobalt (Co) within the series.)

- Lead is significantly lower than Magnesium in the activity series, so it cannot displace Mg2+ ions in a solution.

- Aluminium ranks higher than Silver in the series; thus, it can easily oxidize and replace Silver ions from its solution.

- Cadmium is capable of displacing Copper in solution since it ranks higher than Copper in the activity series.

- Platinum is unable to displace Cobalt from a solution, as it ranks lower than Cobalt in the activity series.

The concentration of O₂ in H₂O can be expressed as ppm

ppm stands for parts per million - mg/kg

indicating the quantity of mg in 1 kg of solution

Here, the mass of O₂ is 0.008 g

Since 1000 mg equals 1 g

the mass of O₂ in mg is calculated as - 0.008 g x 1000 mg/g = 8 mg

The mass of the water amounts to 1000 g

which is the same as 1 kg

thus the mass of water in kg is - 1000 g / 1000 g/kg = 1 kg

therefore, there are 8 mg of O₂ in 1 kg of water

which gives a concentration of O₂ of - 8 mg/kg

this can also be represented as 8 ppm

the final answer is 8 ppm