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siniylev
21 day ago
7

A sample of a certain binary compound contains 6.93 g of silicon and 7.89 g of oxygen. What is the percent composition of the co

mpound?
Chemistry
2 answers:
lions [2.6K]21 day ago
5 0

Given, mass of silicon = 6.93 g

mass of oxygen = 7.89 g

Now calculate the moles of both silicon and oxygen:

Number of moles = \frac{given mass}{molar mass}

Substituting the provided mass values into the formula above:

Number of moles of silicon = \frac{given mass of silicon in g}{molar mass of silicon}

= \frac{6.93 g}{28 g/mol}

= 0.2475 mol

Number of moles of oxygen = \frac{given mass of silicon in g}{molar mass of silicon}

= \frac{7.89 g}{16 g/mol}

= 0.493125 mol

So,

Total moles = number of silicon + number of oxygen moles

= 0.493125 mol+0.2475 mol=0.740625 mol

Percentage composition = \frac{number of moles of an atom}{total number of moles of the compound}\times 100

Finally, input the values in the formula provided:

Percentage composition of silicon= \frac{number of moles of silicon}{total number of moles of the compound}\times 100

Percentage composition of silicon= \frac{0.2475 mol}{0.740625 mol}\times 100

= 33.41 percent

Percentage composition of oxygen= \frac{number of moles of oxygen}{total number of moles of the compound}\times 100

Percentage composition of silicon= \frac{0.493125 mol}{0.740625 mol}\times 100

= 66. 58 percent

Thus, the percent composition of silicon and oxygen is 33.41 percentand 66. 58 percent

KiRa [2.7K]21 day ago
4 0
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