The electric field in a particular space is = (x + 3.6) N/C with x in meters. Consider a cylindrical Gaussian surface of radius
1 answer:
Answer:
a) Ф = 0.016 N / C m, b) q_{int} = 0.14 10⁻¹² C
Explanation:
a) For this scenario, we rely on Gauss's law
Ф = E.ds = /ε₀
As the field points in the x direction, there is no flux through the cylinder walls.
Ф = E A
The area of a circle is
A = π r
Ф = E π r
Ф = (x- 3.6) r
Now, let's compute
Ф = (3.7 -3.6) 0.16
Ф = 0.016 N / C m
b) Using Gauss's law, we have
q_{int} = Ф ε₀
Where the flow is present on both sides, at the face corresponding to x = 0, the flow is zero
q_{int} = 0.016 8.85 10⁻¹²
q_{int} = 0.14 10⁻¹² C
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Answer:
b) TA = TB = TC
Explanation:
- When the blocks are brought into contact and isolated from the environment, they will exchange heat until they achieve thermal equilibrium.
- During this exchange, the hotter body will lose heat, which will be gained by the cooler body.
- The equilibrium state will be established once this equation is satisfied:
- Substituting the initial temperatures T₀A = 300º C and T₀B = 400ºC, while simplifying for equal block masses mA = mB, enables us to solve for the final temperature, Tfin:
- At equilibrium, when both blocks combine, they will yield a uniform final temperature of 350ºC.
- When block C, also at this temperature, makes contact, all three blocks will simultaneously reflect this final temperature of 350 ºC.
- Therefore, option b) is correct.