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just olya
6 days ago
12

Wave-particle duality tells us that wave and particle models apply to all objects whatever the size, so why don't we observe wav

e properties in macroscopic objects?
Physics
1 answer:
inna [2.2K]6 days ago
4 0

Answer:

The wavelengths of macroscopic objects are too brief for detection.

Explanation:

De Broglie wavelength defines the wavelength of an object as:

\lambda=\frac{h}{mv}

where 'h' represents Planck's constant, 'm' denotes the object's mass, and 'v' reflects its velocity.

For macroscopic entities, the mass is significantly higher than that of microscopic ones. Aper the above equation, there's an inverse relationship between an object's mass and its wavelength.

Thus, for significantly large masses, the wavelength is exceedingly short making them untraceable. Consequently, we do not observe wave characteristics in macroscopic objects.

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1/0.0545. The transformation ratio of primary coil turns to secondary coil turns is directly proportional to the voltage transformation occurring. With 6.0 V on the secondary side (output) and 110 V on the primary side (input), the voltage ratio is calculated as 6/110 = 0.0545. This means for each turn in the primary coil, there are 0.0545 turns in the secondary coil.
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11 days ago
A ski lift is used to transport people from the base of a hill to the top. If the lift leaves the base at a velocity of 15.5 m/s
Yuliya22 [2438]
This can be determined using the principle of energy conservation. The ski lift begins with a velocity of v= 15.5 m/s, and all of its kinetic energy Ek converts into potential energy Ep, thus we set Ep equal to Ek.
Because Ek is given by (1/2)*m*v², where m denotes mass and v represents speed, while Ep equals m*g*h, where m is mass, g is 9.81 m/s², and h is height. Now:

Ek=Ep 

(1/2)*m*v²=m*g*h, canceling out the mass,

(1/2)*v²=g*h, rearranging for height by dividing by g,

(1/2*g)*v²=h and substituting the values:

h=12.245 m. The hill's height rounded to the nearest tenth is h=12.25 m.

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Justine is ice-skating at the Lloyd Center what is her final velocity if she accelerates at a rate of 2.0 meters per second for
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2*3.5 = 7m/s

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Incoming solar radiation (light energy) is absorbed by the Earth's surface and converted to outgoing infrared radiation (heat en
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An increase in temperature (Global warming) is observed. The solar radiation is transformed into heat energy absorbed by Earth's surface. In line with the law of conservation of energy, energy can only transition forms rather than disappear. If an increasing quantity of energy accumulates on Earth with minimal release, this imbalance in energy demand leads to a rise in temperature due to excessive heat absorption, largely a result of pollution from fossil fuel combustion releasing CO2 and other harmful emissions. Ordinarily, the residual solar energy would escape back into space, but CO2 and similar contaminants trap this heat, thus elevating Earth's temperature.
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11 days ago
The two sides of the DNA double helix are connected by pairs of bases (adenine, thymine, cytosine, and guanine). Because of the
kicyunya [2264]

Answer:

Explanation:

An image of the bond resulting from the search is attached.

Consider the force directed towards thymine as negative.

For the O-H-N combination:

The resulting force from this combination is:

F=-F_{OH}+F_{ON}\\\\=\frac{Ke^2}{r^2}+\frac{Ke^2}{r'^2}\\\\=Ke^2(\frac{-1}{r^2}+\frac{1}{r'^2})\\\\=(9.0\times 10^9Nm^2/kg^2)(1.6\times 10^{-19}C)^2[\frac{1}{[(0.280-0.110)\times 10^{-9}m]^2}+\frac{1}{0.280\times 10^{-9}m)^2}]\\\\=-5.03354\times 10^{-9}N

In the case of the N-H-N combination:

The total force acting from this combination is:

F'=F_{NN}-F_{HN}\\\\=\frac{Ke^2}{r^2}-\frac{Ke^2}{r'^2}\\\\=Ke^2(\frac{-1}{r^2}+\frac{1}{r'^2})\\\\=(9.0\times 10^9Nm^2/kg^2)(1.6\times 10^{-19}C)^2[\frac{1}{[0.300\times 10^{-9}m]^2}-\frac{1}{((0300-0..110)\times 10^{-9})m)^2}]\\\\=-3.822\times 10^{-9}N

The force that thymine applies on adenine is:

F_{net}=F+F'\\\\=-5.03354\times 10^{-9}N-3.822\times 10^{-9}N\\\\=-8.8558\times 10^{-9}N

When rounded to three significant figures, the net force is 8.86\times 10^{-9}N

b)

The negative value indicates that the force is attractive, as it is aimed towards thymi.

c)

The force acting on the electron due to the proton is:

F=\frac{Ke^2}{r^2}\\\\=\frac{(9.0\times 10^9Nm^2/C^2)(1.6\times 10^{-9}C)^2}{(5.29\times 10^{-11}m)^2}\\\\=8.233\times 10^{-8}N

Since the electron and proton carry opposite charges, the force on the electron points towards the proton.

d)

The ratio of the above forces is:

\frac{F}{F_{net}}=\frac{8.233\times 10^{-8}N}{8.233\times 10^{-8}N}\\\\=9.3

Therefore, the bonding strength of the electron in the hydrogen atom is 9.3 times greater than the bonding force between adenine and thymine molecules.

5 0
24 days ago
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