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Luda
1 month ago
9

A rigid tank is divided into two equal parts by a partition. Initially one side of the tank contains 5 kg of water at 200 kPa an

d 25 C, and the other side is evacuated (i.e. there is nothing there, not even air). The partition is then removed and the water expands into the entire tank. The water is allowed to exchange heat with its surroundings until the temperature in the tank returns to the initial value of 25 C. Determine the heat transfer into the water for this process in kJ.
Physics
1 answer:
Ostrovityanka [3.2K]1 month ago
8 0
In the system analyzed, there is no heat transfer as the temperature remains constant at 25°C before and after the interaction. The heat exchange can be expressed by the equation Q = mCΔT, indicating that if ΔT equals zero, there is evidently no heat gain or loss. Considering the vacuum side of the tank, where m equals 0, we find Q equals 0 KJ, signifying that the system experienced no heat exchange.
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If an electronic circuit experiences a loss of 3 decibels with an input power of 6 watts, what would its output power be, to the
Yuliya22 [3333]

Answer:

The output power of the circuit is 3 Watts.

Given:

a loss in decibels = 3 dB

Input power = 6 Watts

To find:

What is the output power?

Formula used:

Output power = Input power × loss in ratio

Solution:

3 dB loss corresponds to a ratio of 0.5

Output power can be calculated as follows:

Output power = Input power × loss in ratio

Output power = 6 × 0.5

Output power = 3 Watts

Therefore, the output power of the circuit is 3 Watts.

4 0
1 month ago
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A point charge with charge q1 is held stationary at the origin. A second point charge with charge q2 moves from the point (x1, 0
kicyunya [3294]

Answer:

W=kq_1q_2(\dfrac{1}{x_1}-\dfrac{1}{\sqrt{x_2^2+y_2^2}})

Explanation:

The position of the charge q₁ is established at (0,0)

Meanwhile, the charge q₂ is located at (x₁,0)

Thus, the electric potential energy between these two charges is determined by:

U_1=k\dfrac{q_1q_2}{x_1}

Now, the location of charge q₂ shifts from (x₁,0) to (x₂,y₂). The updated electric potential energy between the charges can be represented as:

U_2=k\dfrac{q_1q_2}{\sqrt{x_2^2+y_2^2}}

According to the work-energy theorem, the alteration in potential energy corresponds to the work performed. This is expressed mathematically as:

W=-\Delta U

W=-(U_2-U_1)

W=(U_1-U_2)

W=(k\dfrac{q_1q_2}{x_1}-k\dfrac{q_1q_2}{\sqrt{x_2^2+y_2^2}})

W=kq_1q_2(\dfrac{1}{x_1}-\dfrac{1}{\sqrt{x_2^2+y_2^2}})

Consequently, the work done by the electrostatic force on the moving charge is kq_1q_2(\dfrac{1}{x_1}-\dfrac{1}{\sqrt{x_2^2+y_2^2}}). Therefore, this concludes the solution.

3 0
1 month ago
You're riding a unicorn at 25 m/s and come to a uniform stop at a red light 20m away. What's your acceleration?
Ostrovityanka [3204]

The result is -15.625 m/s².


Acceleration signifies the alteration of velocity over a specified duration. It can be calculated with this formula:


a = \dfrac{vf-vi}{t}

Where:

vf = final velocity

vi = initial velocity

t = time

Let’s examine the information provided in your query:

Initially, the vehicle was traveling at 25 m/s before coming to a halt. Thus, it was in motion and subsequently ceased moving, indicating that the final velocity is 0 m/s.


However, we notice that the problem does not provide a time value. We need to determine the time taken from when it was in motion to when it reached the traffic light located 20 m away.


The time can be calculated using the kinematics equation:

d = \dfrac{vi+vf}{2} *t


We derive the equation by substituting the known values first.

20m = \dfrac{25m/s+0m/s}{2}(t)

20m = 12.5m/s{2}(t)

\dfrac{20m}{12.5m/s}=t
1.6s=t

The duration from when it was in motion until it stopped is 1.6s. Now we can utilize this in our acceleration calculation.


a = \dfrac{0m/s-25m/s}{1.6s}

a = \dfrac{-25m/s}{1.6s}

a = -15.625m/s^{2}


It is important to note that the acceleration is negative, indicating the vehicle slowed down.

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1 month ago
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Sav [3153]
A left turn lane is designated for vehicles making left turns. Vehicles must completely enter this lane and wait for a clear path before proceeding with the turn. It is not permissible for a vehicle to be partially in and out of the lane, as this obstructs traffic and creates hazardous conditions.
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In the demolition of an old building, a 1,300 kg wrecking ball hits the building at 1.07 m/s2. Calculate the amount of force at
Ostrovityanka [3204]
The force can be determined using the equation F (force) = mass * acceleration. The unit of measurement, N (Newton), is equivalent to kilogram-meter/seconds2.
Thus, F= 1300 kg * 1.07 m/s2 = 1391 N.
The resultant value is 1391 N.
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1 month ago
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