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10 days ago

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An ice cube with a volume of 45.0ml and a density of 0.9000g/cm3 floats in a liquid with a density of 1.36g/ml. what volume of t

he cube is submerged in the liquid

1 answer:

VMariaS [2.8K]10 days ago

5 0

Response: The volume of the cube that is underwater is 29.8 mL

Clarification:

Initially, we need to find the mass of the ice.

Equation applied:

$\text{Mass of ice}=\text{Density of ice}\times \text{Volume of ice}$

Provided information:

Ice density = $0.9000g/cm^3=0.9000g/mL$

Volume of ice = 45.0 mL

$\text{Mass of ice}=0.9000g/mL\times 45.0mL$

$\text{Mass of ice}=40.5g$

The cube displaces 40.5 g of liquid to float.

Next, we will ascertain how much of the cube is submerged in the liquid.

$\text{Volume of ice}=\frac{\text{Mass of liquid}}{\text{Density of liquid}}$

$\text{Volume of ice}=\frac{40.5g}{1.36g/mL}$

$\text{Volume of ice}=29.8mL$

Therefore, the submerged portion of the cube is 29.8 mL

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Squaring both sides gives us:

$(m \times \nu)^{2}$ = $(3.6 \times 10^{-26} J/m)^{2}$

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