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shepuryov
1 month ago
5

Sixteen students are randomly selected from each grade level at a high school and asked about their eating habits. This sampling

technique is called:
Mathematics
1 answer:
PIT_PIT [12.4K]1 month ago
8 0

Answer:

stratified random sampling method

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The present age of Alex is ‘y’ years. Answer the following
PIT_PIT [12445]

Answer:

(a) What will his age be after 5 years?

"5 + y" years old

(b) What was his age 6 years ago?

"y - 6" years old

(c) If his grandfather’s age is five times his, how old is his grandfather?

"5y" years old

(d) His father is 6 years older than three times his age. How old is his father?

"6 + 3y" years old

Note: Disregard the quotation marks, ""

5 0
2 months ago
Read 2 more answers
2 Tables. A 2-column table with 4 rows is titled Table 1. Column 1 has entries 2, 4, 6, 8. Column 2 has entries 3, 6, 9, 12. A 2
tester [12383]

Response:

2:3 is

✔ lesser than

5:6

10:12 is

✔ greater than

6:9

The ratios shown in Table 1 are

✔ smaller than

those in Table 2

Step-by-step explanation:

6 0
1 month ago
Integrated circuits from a certain factory pass a particular quality test with probability 0.75. The outcomes of all tests are m
tester [12383]

Answer:

The anticipated number of tests required to identify 680 acceptable circuits is 907.

Step-by-step explanation:

For any circuit, there are two potential results: it either passes the test or it fails. The likelihood of passing is independent between circuits. Therefore, we apply the binomial probability distribution to address this scenario.

Binomial probability distribution

This distribution calculates the chance of obtaining exactly x successes across n trials, where x has only two possible outcomes.

To find the expected number of trials to achieve r successes with a probability p, the formula is given by:

E = \frac{r}{p}

Circuits from a specific factory pass a certain quality evaluation with a probability of 0.75.

Thus, to determine the expected number of tests needed for 680 acceptable circuits, let’s denote this as E where r = 680.p = 0.75

E = \frac{r}{p}

E = \frac{680}{0.75}

E = 907

The expected number of tests necessary to find 680 acceptable circuits is 907.

8 0
2 months ago
To get the best deal on a microwave oven, Jeremy called six appliance stores and asked the cost of a specific model. The prices
babunello [11817]

Answer:

Step-by-step explanation:

The prices he received quotes for are as follows: $663, $273, $410, $622, $174, $374

To begin, we will find the average.

Average = total of data points/ number of data points.

Total of data points =

663 + 273 + 410 + 622 + 174 + 374

= 2516

Total count = 6

Average = 2516/6 = 419.33

Standard deviation = √summation(x - m)^2/n

summation(x - m)^2/n = (663 - 419.33)^2 + (273 - 419.33)^2 + (410 - 419.33)^2 + (622 - 419.33)^2 + (174 - 419.33)^2 + (374 - 419.33)^2

= 179417.9334/6 = 29902.9889

Standard deviation = √29902.9889

= 172.9

6 0
1 month ago
Tickets to a play are $12.00 for adults. Children receive a discount and only have to pay $8.00. If 40 people attend the play an
AnnZ [12381]
There were 30 adults and 10 children, totaling 40 attendees. Just sum them together.
3 0
1 month ago
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