For thorough details and necessary calculations, please refer to the attachment.
Answer:
2023857702.507 m
Explanation:

Using Newton's law of gravitation:
G = gravitational constant
m_shrew = 50 g
m_elephant = 5 × 10^3 kg
r_earth = Earth's radius, 6400 km or 6,400,000 m
m_earth = Earth's mass
Equate the gravitational forces:
G m_shrew m_earth / r_earth^2 = G m_elephant m_earth / r^2
Cancel common terms on both sides:
m_shrew / r_earth^2 = m_elephant / r^2
Rearranged to solve for r^2:
r^2 = (m_elephant × r_earth^2) / m_shrew
Substituting the values:
r^2 = 4.096 × 10^{13}
Taking square root gives:
r = 2,023,857,702.507 m
Response:

Explanation:
Torque is defined as:

where
F is the force's magnitude,
d represents the distance from where the force is applied to the center of rotation,
and is the angle between the force's direction and d.
In this question, we have:
, the force
, the distance of applying the force from the center (0,0)
, and the angle between the force's direction and a.
Thus, the torque is

Answer:
10.4 m/s
Explanation:
To solve this problem, we can apply the following SUVAT equation:

where
v denotes the final velocity
u represents the initial velocity
a stands for acceleration
t denotes time
For the diver in our case, the values are:
the initial velocity is positive since it is directed upwards

the downward acceleration from gravity is negative

By substituting t = 1.7 s, we can find the velocity at the moment the diver strikes the water:
The negative sign indicates a downward direction; hence, the diving speed will be 10.4 m/s.
Answer:
The distance measures 
Explanation:
According to the problem statement,
The box's width is
There is a gap of length 
The first spring's natural length is 
The spring constant for the first spring is 
The second spring has a natural length of 
The second spring's spring constant is 
We denote the distance from the center of the box to the left edge as x.
At equilibrium,
The force exerted by the first spring is

while the force from the second spring is
![F_2 = k_2 * [ 0.9 - (0.9 -x)]](https://tex.z-dn.net/?f=F_2%20%3D%20%20k_2%20%2A%20%5B%200.9%20-%20%280.9%20-x%29%5D)
Thus, at equilibrium,

Substituting values gives us
![k_1 * (0.8 -x) = k_2 * [ 0.9 - (0.9 -x)]](https://tex.z-dn.net/?f=k_1%20%2A%20%280.8%20-x%29%20%3D%20%20%20%20k_2%20%2A%20%5B%200.9%20-%20%280.9%20-x%29%5D)
which leads to
![200 * (0.8 -x) = 350 * [ 0.9 - (0.9 -x)]](https://tex.z-dn.net/?f=200%20%2A%20%280.8%20-x%29%20%3D%20%20%20%20350%20%2A%20%5B%200.9%20-%20%280.9%20-x%29%5D)
resulting in

and finally,

this simplifies to
