V - wind speed;
53° - 35° = 18°
v² = 55² + 40² - 2 · 55 · 40 · cos 18°
v² = 3025 + 1600 - 2 · 55 · 40 · 0.951
v² = 440.6
v = √440.6
v = 20.99 ≈ 21 m/s
Conclusion: The wind speed calculates to 21 m/s.
Answer:
I'm uncertain
Explanation:
since I didn't provide a correct answer, continue with my inquiries and you can use 'I'm uncertain' for 100 points.
The intensity of the sound increases because sound waves are mechanical waves, meaning they cannot move through a vacuum and require a medium to propagate.
Idhdhdhdhdjdfjfjnfnfnffnfnfnfnfnfjfnfjfoddidjdifjdjffucjfjffjfuf
The frequency detected is 394 Hz. This question pertains to the Doppler effect, outlined by the equation fo = {c + vo}/{c - vs} × f. Here, fo is the observed frequency, c denotes sound speed at 345 m/s, vo is the observer's velocity of 9.5 m/s, and vs refers to the source's velocity of -9.5 m/s (the negative indicates opposite directions). The source's frequency is given as 394 Hz. Substituting the values leads to fo = {345 + 9.5}/{345 + 9.5} × 394. Simplifying yields fo = (354.5/354.5) × 394 = 1 × 394 = 394 Hz.
