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natali 33
5 days ago
9

What is the kinetic energy of a 100 kg object that is moving with a speed of 12.5m/s

Physics
1 answer:
Softa [2.9K]5 days ago
7 0

The formula for the kinetic energy of any object in motion is

                           (1/2) (mass) (velocity²).

For the object you've mentioned, it translates to

                            (1/2) (100 kg) (12.5 m/s)²

                         =      (50 kg)  (156.25 m²/s²)

                         =              7,812.5 joules  
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The PVT behavior of a certain gas is described by the equation of state: P(V − b) = RT where b is a constant. If in addition CV
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6 0
8 days ago
An adult elephant has a mass of about 5.0 tons. An adult elephant shrew has a mass of about 50 grams. How far r from the center
Maru [3272]

Answer:

2023857702.507 m

Explanation:

f=\frac{GMm}{r^{2} }

Using Newton's law of gravitation:

G = gravitational constant

m_shrew = 50 g

m_elephant = 5 × 10^3 kg

r_earth = Earth's radius, 6400 km or 6,400,000 m

m_earth = Earth's mass

Equate the gravitational forces:

G m_shrew m_earth / r_earth^2 = G m_elephant m_earth / r^2

Cancel common terms on both sides:

m_shrew / r_earth^2 = m_elephant / r^2

Rearranged to solve for r^2:

r^2 = (m_elephant × r_earth^2) / m_shrew

Substituting the values:

r^2 = 4.096 × 10^{13}

Taking square root gives:

r = 2,023,857,702.507 m

4 0
1 month ago
What is the torque τa about axis a due to the force f⃗ ? express the torque about axis a at cartesian coordinates (0,0)?
Yuliya22 [3234]

Response:

\tau_a = F a sin \theta

Explanation:

Torque is defined as:

\tau = F d sin \theta

where

F is the force's magnitude,

d represents the distance from where the force is applied to the center of rotation,

\theta and is the angle between the force's direction and d.

In this question, we have:

F, the force

a, the distance of applying the force from the center (0,0)

\theta, and the angle between the force's direction and a.

Thus, the torque is

\tau_a = F a sin \theta

5 0
27 days ago
In springboard diving, the diver strides out to the end of the board, takes a jump onto its end, and uses the resultant spring-l
Keith_Richards [3153]

Answer:

10.4 m/s

Explanation:

To solve this problem, we can apply the following SUVAT equation:

v=u+at

where

v denotes the final velocity

u represents the initial velocity

a stands for acceleration

t denotes time

For the diver in our case, the values are:

the initial velocity is positive since it is directed upwards

u=+6.3 m/s

the downward acceleration from gravity is negative

a=g=-9.8 m/s^2

By substituting t = 1.7 s, we can find the velocity at the moment the diver strikes the water:

v=+6.3 + (-9.8)(1.7)=-10.4 m/sThe negative sign indicates a downward direction; hence, the diving speed will be 10.4 m/s.

3 0
8 days ago
Read 2 more answers
A 10 cm wide box is held between two springs in a 1 m gap on a frictionless surface. The left spring has a natural length of 80
Maru [3272]

Answer:

The distance measures x =0.291 \ m

Explanation:

According to the problem statement,

The box's width is b = 10 \ cm = \frac{10}{100} = 0.10 \ m

There is a gap of length l = 1\ m

The first spring's natural length is y = 80 \ cm = \frac{80 }{100} = 0.8 \ m

The spring constant for the first spring is k_1 = 200 N/m

The second spring has a natural length of z = 90 \ cm = \frac{90}{100} = 0.9 \ m

The second spring's spring constant is k_2 = 350 \ N/m

We denote the distance from the center of the box to the left edge as x.

At equilibrium,

The force exerted by the first spring is

F_1 = k_1 * (0.8 -x)

while the force from the second spring is

F_2 = k_2 * [ 0.9 - (0.9 -x)]

Thus, at equilibrium,

F_1 = F_2

Substituting values gives us

k_1 * (0.8 -x) = k_2 * [ 0.9 - (0.9 -x)]

which leads to

200 * (0.8 -x) = 350 * [ 0.9 - (0.9 -x)]

resulting in

160 -200x) = 350x

and finally,

160 =550x

this simplifies to

x =0.291 \ m

6 0
1 month ago
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