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Damm
11 days ago
12

In a hexagonal-close-pack (hcp) unit cell, the ratio of lattice points to octahedral holes to tetrahedral holes is 1:1:2. What i

s the general formula for a compound if anions occupy the hcp lattice points and cations occupy half of the tetrahedral holes? AB A3B AB2 A2B What is the general formula for a compound if anions occupy the hcp lattice points and cations occupy all the tetrahedral holes? AB A2B AB2 A3B
Chemistry
1 answer:
VMariaS [2.9K]11 days ago
6 0

Clarification:

Within a hexagonal close-packed (HCP) unit cell, the ratio of lattice points to octahedral and tetrahedral holes is  1: 1: 2.

Defining the:

Number of lattice points = 1x.

Number of octahedral points = 1x

Number of tetrahedral points = 2x

Assuming anions occupy the HCP lattice points and cations fill half of the tetrahedral holes.

The number of anions in the HCP lattice points, A= 1x

The cation count at tetrahedral points, B =  \frac{2x}{2}=x

Thus, the compound's formula will be = A_{1x}B_{1x}=AB

If anions occupy the HCP lattice points and cations take all of the tetrahedral holes, the number of anions remains as A= 1x

The count of cations at tetrahedral points would now be B = 2x

Thus, the formula for the compound will be = A_{1x}B_{2x}=AB_2

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