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GuDViN
9 days ago
8

The empirical formula of a gaseous fluorocarbon is CF2. At a certain temperature and pressure, a 1-L volume holds 8.93 g of this

fluorocarbon, whereas under the same conditions, the 1-L volume holds only 1.70 g gaseous fluorine (F2). Determine the molecular formula of this compound.
Chemistry
1 answer:
lions [985]9 days ago
3 0

Answer:

C₄F₈

Explanation:

To find the mass, we will use the mole ratio.

The molar mass of carbon is 12.0107 g/mol.

For fluorine gas, the molar mass is 37.99681 g/mol.

Let x represent the mass of carbon.

The provided mass of fluorine is 1.70 g.

Setting up the proportion: x / 12.01067 = 1.70 / 37.99687.

Now, we will cross-multiply.

This results in: x = (1.70 × 12) / 37.99687 = 20.4 / 37.99687 = 0.53688 g.

To find the mass of one mole of CF₂, we add: 0.53688 + 1.70 = 2.23688 g.

The moles of CF₂ are calculated as: 8.93 g / 2.23688 = 3.992, which rounds to approximately 4.

The molecular formula for CF₂ is then 4(CF₂) = C₄F₈

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