Answer:
Explanation:
Assuming all calculations occur at standard pressure and a temperature of -1.72°C :
Where
is the number of moles of hydrogen
is the mass of hydrogen
is the density of hydrogen
The empirical formula of a gaseous fluorocarbon is CF2. At a certain temperature and pressure, a 1-L volume holds 8.93 g of this
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Answer:
There are 5.5668 moles of water for every mole of CuSO₄.
Explanation:
The mass of anhydrous CuSO₄ is:
23.403g - 22.652g = 0.751g.
mass of crucible + lid + CuSO₄ - mass of crucible + lid
Given that the molar mass of CuSO₄ is 159.609g/mol, we calculate the moles:
0.751g × = 4.7052x10⁻³ moles CuSO₄
The mass of water in the initial sample is:
23.875g - 0.751g - 22.652g = 0.472g.
mass of crucible + lid + CuSO₄ hydrate - CuSO₄ - mass of crucible + lid
As the molar mass of H₂O is 18.02g/mol, we find the moles:
0.472g × = 2.6193x10⁻² moles H₂O
The mole ratio of H₂O to CuSO₄ is:
2.6193x10⁻² moles H₂O / 4.7052x10⁻³ moles CuSO₄ = 5.5668
This indicates there are 5.5668 moles of water per mole of CuSO₄.
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Answer:
The empirical formula is =
The Valproic acid formula is =
Explanation:
Mass of the produced water = 0.166 g
Molar mass of water = 18 g/mol
The moles of are calculated as 0.166 g /18 g/mol = 0.00922 moles.
In 1 mole of water, there are 2 moles of hydrogen atoms.
Thus,
Moles of H = 2 x 0.00922 = 0.01844 moles
Each hydrogen atom's molar mass is 1.008 g/mol.
Hydrogen mass in the molecule = 0.01844 x 1.008 = 0.018588 g
Mass of produced carbon dioxide = 0.403 g
Molar mass of carbon dioxide = 44.01 g/mol
The moles of are calculated as 0.403 g /44.01 g/mol = 0.009157 moles.
Each carbon atom's presence is 1 mole in 1 mole of carbon dioxide.
So,
Moles of C = 0.009157 moles
The molar mass of carbon is 12.0107 g/mol.
Carbon mass in molecule = 0.009157 x 12.0107 = 0.11 g
Since Valproic acid comprises only hydrogen, oxygen, and carbon, the oxygen mass in the sample = Total mass - Carbon mass - Hydrogen mass.
The sample's overall mass = 0.165 g.
Oxygen mass in the sample = 0.165 - 0.11 - 0.018588 = 0.036412 g
The molar mass of oxygen is 15.999 g/mol.
Moles of O = 0.036412 / 15.999 = 0.002276 moles
Taking the simplest ratio for H, O, and C yields:
0.01844: 0.002276: 0.009157
= 8: 1: 4
The empirical formula becomes
While molecular formulas detail the precise count of atoms for each element, empirical formulas represent the simplest form or reduced ratio of these elements in the compound.
Consequently,
The molecular mass equals n × Empirical mass.
Here, n is a positive integer from 1, 2, 3...
Empirical mass = 4×12 + 8×1 + 16 = 72 g/mol.
Molar mass = 144 g/mol.
Thus,
The molecular mass = n × Empirical mass.
144 = n × 72
⇒ n = 2
The Valproic acid formula is =
Answer:
A pressure of 137.14 MPa exists 10,000 m beneath the ocean surface.
At this same depth, the density measures 2039 kg/m3.
Explanation:
P0 and ρ0 symbolize the pressure and density at sea level (indicative of atmospheric conditions). With an increase in ocean depth, both pressure and density likewise rise.
The relationship between pressure and density can be expressed as:
By rearranging
This equation allows for computation of P at 10,000 m beneath the ocean's surface:
The density found at a depth of 10,000 m in the ocean is