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GalinKa
1 month ago
13

Suppose that you purchased a water bed with the dimensions 2.55 m à 2.53 dm à 245 cm. what mass of water does this bed contain

Physics
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Incoming solar radiation (light energy) is absorbed by the Earth's surface and converted to outgoing infrared radiation (heat en
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Isaac throws an apple straight up from 1.0 m above the ground, reaching a maximum height of 35 meters. Neglecting air resistance
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The velocity of the apple right before impact with the ground is approximately 26.2005 m/s, while its initial velocity was about 25.8235 m/s.

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A 6.0-cm-diameter, 11-cm-long cylinder contains 100 mg of oxygen (O2) at a pressure less than 1 atm. The cap on one end of the c
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Explanation:

Here is the provided information:

Mass of oxygen contained = 100 mg = 100 \times 10^{-3} g

Thus, the moles of oxygen can be calculated using the following formula:

n = \frac{100 \times 10^{-3}}{32}

= 3.125 \times 10^{-3} moles

Diameter of the cylinder = 6 cm = 6 \times 10^{-2} m

= 0.06 m

Next, we can determine the cross-sectional area (A) as follows:

A = \pi \times \frac{(0.06)^{2}}{4}

= 2.82 \times 10^{-3} m^{2}

Length of the tube = 11 cm = 0.11 m

Thus, the volume (V) is given by 2.82 \times 10^{-3} \times 0.11

= 3.11 \times 10^{-4} m^{3}

For our calculations, we'll assume the internal pressure is P.

Moreover, P_{atm} = 100 kPa = 100000 Pa,

The pressure difference amounts to 100000 - P

Thus, the force required to open is calculated as follows:

Force = Pressure difference × A

= (100000 - P) \times 2.82 \times 10^{-3}

We are provided with the information that the force equals 173 N.

Thus,

(100000 - P) \times 2.82 \times 10^{-3} = 173

By solving, we find,

P = 3.8650 \times 10^{4} Pa

= 38.65 kPa

Using the ideal gas equation, PV = nRT

Hence, we will input the values into the equation as follows:

PV = nRT

38.65 \times 3.11 \times 10^{-4} = 3.125 \times 10^{-3} \times 8.314 \times T

T = 462.66 K

Consequently, we can deduce that the gas temperature is 462.66 K.

6 0
2 months ago
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