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Montano1993
11 days ago
14

A high-jumper, having just cleared the bar, lands on an air mattress and comes to rest. Had she landed directly on the hard grou

nd, her stopping time would have been much shorter. Using the impulse-momentum theorem as your guide, determine which one of the following statements is correct.a. the air mattress exerts the same impulse, but a greater net average force, on the high-jumper than does the hard ground
b. the air mattress exerts a greater impulse, and a greater net average force, on the high-jumper than does the hard ground
c. the air mattress exerts a smaller impulse, and a smaller net average force, on the high-jumper than does the hard ground
d. the air mattress exerts a greater impulse, but a smaller net average force, on the high-jumper than does the hard ground
e. the air mattress exerts the same impulse, but a smaller net avg force, on the hj than hg
Physics
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4. A 505-turn circular-loop coil with a diameter of 15.5 cm is initially aligned so that
Ostrovityanka [3204]

The intensity of the magnetic field is 4.8\cdot 10^{-5} T

Explanation:

According to Faraday's Law, the magnitude of the induced electromotive force (emf) in the coil corresponds to the rate of flux change that links through the coil:

\epsilon = \frac{N\Delta \Phi}{\Delta t} (1)

where

N = 505 represents the number of turns in the coil

\Delta \Phi is the variation in magnetic flux through the coil

\Delta t = 2.77 ms = 2.77\cdot 10^{-3} s indicates the time interval

\epsilon = 0.166 V

Rotating the coil from perpendicular to parallel alignment with the Earth's magnetic field results in the final flux equaling zero, making the magnitude of flux change simply the initial flux:

\Delta \Phi = B A cos \theta

where

B denotes the intensity of the magnetic field

A signifies the area of the coil

\theta=0^{\circ} represents the angle between the normal to the coil and the field

The area of the coil can be expressed as

A=\pi r^2

where

r=\frac{15.5 cm}{2}=7.75 cm = 7.75\cdot 10^{-2} m outlines its radius

By substituting all values into equation (1) and solving for B, we obtain:

\epsilon= \frac{NB\pi r^2 cos \theta}{\Delta t}\\B=\frac{\epsilon \Delta t}{\pi r^2 cos \theta}=\frac{(0.166)(2.77\cdot 10^{-3})}{(505)\pi (7.75\cdot 10^{-2})^2(cos 0^{\circ})}=4.8\cdot 10^{-5} T

For further reading on magnetic fields:

8 0
2 months ago
Read 2 more answers
A 620-g object traveling at 2.1 m/s collides head-on with a 320-g object traveling in the opposite direction at 3.8 m/s. If the
Keith_Richards [3271]

Answer:

No kinetic energy is lost as the collision is elastic.

Explanation:

Throughout an elastic collision, both momentum and kinetic energy remain conserved.

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6 0
3 months ago
Read 2 more answers
A hydraulic lift raises a 2000 kg automobile when a 500 N force is applied to the smaller piston. If the smaller piston has an a
kicyunya [3294]

Answer:

The cross-sectional area of the larger piston is 392cm ^{2}[/tex]

Explanation:

To find the solution, we apply the following equation:

Pascal's principle: F=P*A   Formula (1)

F=Force applied to the piston

P: Pressure

A= Area of the piston

Nomenclature:

Fp= Force on the primary piston= 500N

W= weight of the car =m*g=2000kg*9.8m/s2= 19600N

Fs= Force on the secondary piston= W = 19600N

Ap= Primary piston area=10cm^{2} =10*10^{-4}m^{2}

As= Area of the secondary piston=?

Pressure applied on one side is distributed to all liquid molecules since liquids are incompressible.

From equation (1)

P=F/A

Pp=Ps

\frac{Fp}{Ap} = \frac{Fs}{As}

As= \frac{Fs*Ap}{Fp}

As=\frac{19600*10*10^{-4} }{500}

As=0.0392m^{2} =0.0392*10^{4}cm^{2}

As=392cm ^{2}

5 0
3 months ago
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