Find the element that makes plumbing pipes. is it a metal nonmetal or metalloid

To address this issue, we can apply the following equation:

w = (mass of solute) / (mass of solution)

w - percentage

It is important to note that the mass of the solution is the sum of the mass of the solute and the mass of the water.

<span>w = mass CaCl2/(mass of water + mass of CaCl2)
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mass of water = x

0.35 = 36 / (x + 36)

0.35 × (x + 36) = 36

0.35x + 12.6 = 36

0.35x = 23.4

x = 66.86 g of water is required

The result is 0.14303691.

Carbon-13 (¹³C) is a stable isotope of carbon with a mass number of 13, composed of six protons and seven neutrons.

Isotopes are elements that share the same atomic number but have different mass numbers, meaning they have a varying number of neutrons.

ω(¹³C) = 1.10% ÷ 100%.

ω(¹³C) = 0.0110; this indicates the natural abundance of carbon-13.

m(¹³C) = 13.003355; the atomic mass assigned to carbon-13.

ω(¹³C) · m(¹³C) = 0.0110 · 13.003355.

ω(¹³C) · m(¹³C) = 0.14303691.

Answer:

The revised net worth rounded to three significant figures is $80.2 billion.

The donation to charity amounts to $100,250,000.

Explanation:

Initial net worth is $77.0 billion.

Stock gains are $3.20 billion.

Calculating new net worth: $77.0 billion + $3.20 billion = $80.20 billion.

Hence, new net worth to three significant figures is $80.2 billion.

One-eighth of a percent is calculated as (1/8 x 1) / 100 = 0.00125.

The charitable contribution amounts to 0.00125 X $80.2 billion = $100,250,000.

Alternatively, $80,200,000,000 divided by 100 results in $802,000,000.

To find the answer, start by calculating the total mass of the copper utilized:

Copper used = 100 pennies x 3.0g Cu per penny = 300.0 g Cu

Next, identify the path and molar ratios from Cu produced back to CuFeS2 needed using the established balanced reactions:

1 Cu2S from 2 CuS; 2Cu from 1 Cu2S; 2CuS from 2CuFeS2
Thus, 2Cu comes from 2CuFeS2, indicating a 1:1 molar ratio.

Then convert grams of Cu to moles and grams of CuFeS2:
= 300.0 g Cu * 1 mol Cu/63.546g Cu * 2 mol CuFeS2/2 moles Cu

= 4.72 moles CuFeS2

The required amount of chalcopyrite mined = 4.72 moles CuFeS2 * 183.54 g CuFeS2/1 mole CuFeS2 = 866.49 g CuFeS2