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21 day ago

What is the volume of 43.7 g of helium at stp?

Chemistry

2 answers:

castortr0y [1.5K]20 days ago

0 0

Answer: The helium gas occupies a volume of 244.72 liters.

Explanation: Provided,

Mass of helium = 43.7 g

Molar mass of helium = 4 g/mole

At standard temperature and pressure, 1 mole of gas occupies 22.4 liters.

First, we will calculate the number of moles of helium.

$\text{Moles of He}=\frac{\text{Mass of He}}{\text{Molar mass of He}}=\frac{43.7g}{4g/mole}=10.925mole$

Next, we will find the volume of helium.

Since 1 mole of helium gas occupies 22.4 liters, then 10.925 moles of helium gas will occupy $10.925\times 22.4=244.72$ liters.

Thus, the volume of helium gas is 244.72 liters.

Tems11 [1.4K]20 days ago

0 0

The volume of helium amounts to 244.72 liters.
The mass of helium is 43.7 g.
To find the number of moles: n(He) = m(He) ÷ M(He).
Calculating gives n(He) = 43.7 g ÷ 4 g/mol.
Thus, n(He) equals 10.925 mol.
The volume of helium can be calculated as V(He) = n(He) · 22.4 L/mol.
This results in V(He) = 10.925 mol · 22.4 L/mol.
So, V(He) is 244.72 L.
Vm signifies the molar volume at standard temperature and pressure.
n stands for the amount of substance.

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