C. The molecule N₂ does not undergo transitions in electronic energy levels due to visible light, whereas transitions occur in I₂ molecules due to visible light.
Explanation:
Molecule absorption of light results in electronic transitions from a ground level to an elevated level matching the energy of the absorbed light.
For nitrogen (N₂), permissible electronic transitions require energy differences corresponding to ultraviolet photon energy. Thus, nitrogen remains colorless as it does not absorb visible light. In contrast, iodine (I₂) facilitates electronic transitions corresponding to visible light photon energies, which gives iodine vapors their violet hue.
Learn more about:
electronic transitions
The quantity is 6.074 X 10¹⁸ molecules. To calculate the molecular weight (MM) of the compound C₂₇H₄₆O, we use the formula: 27*(MM of C) + 46*(MM of H) + (MM of O). This leads to: 27*(12.0107) + 46* (1.00784) + (15.999) = 324.2889 + 46.36064 + 15.999 = 386.64854 g. The molar mass of any compound indicates the number of molecules found in one mole, which is 6.022 X 10²³ (Avogadro's number). So, if 386.64854 g of C₂₇H₄₆O consists of 6.022 X 10²³ cholesterol molecules, we can determine how many molecules are found in a deposit of 3.9mg or 0.0039g of C₂₇H₄₆O by using the unitary method. Number of molecules = 6.074 X 10¹⁸ molecules.
Answer:
To facilitate a swifter reaction, remove the outer sodium oxide layer that has developed
Explanation:
The rationale for not utilizing a paper towel to dab your metal is:
Eliminate the outer sodium oxide layer that has formed to enable a quicker reaction.
Dabbing involves applying quantities of a cannabis concentrate that vaporizes on a heated surface.
Using an ordinary paper towel to dab that metal won’t effectively remove the outer oxide layer.
Answer:1
Explanation:I know this is correct because I got it right.
