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9 days ago

A proton has mass 1.7 ✕ 10−27 kg. what is the magnitude of the impulse required to increase its speed from 0.991c to 0.994c?

1 answer:

6 0

Impulse can be equated to the force associated with momentum change, expressed as F*t = mv - mu
Given the mass and speed values are provided, apply the formula from the right-hand side:
mass, m = 1.7 x 10^27 kg
initial velocity, u = 0.991 x (3 x 10^8) = 2.973 x 10^8
final velocity, v = 0.994 x (3 x 10^8) = 2.982 x 10^8
Consequently, the calculation is:
Impulse = mv - mu
= [(1.7 x 10^27) x (2.982 x 10^8)] - [(1.7 x 10^27) x (2.973 x 10^8)]
= (5.0694 x 10^35) - (5.0694 x 10^35)
= 0

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