1. Saturated hydrocarbons can either be cyclic or acyclic structures. 2. An unsaturated hydrocarbon molecule contains at least one double bond. Explanation: Greetings, hydrocarbons are defined as the most basic organic compounds comprising only carbon and hydrogen. Therefore, we can eliminate the third statement since ethylenediamine is identified as an amine (an organic structure containing NH groups). Consequently, as saturated hydrocarbons only exhibit single bonds between carbons and carbon-hydrogens, they may be cyclic (ring-shaped) or acyclic (not ring-shaped), establishing the truth of the first statement. Finally, since saturated hydrocarbons exclusively feature single bonds while unsaturated hydrocarbons can exhibit double or triple bonds between carbons and carbon-hydrogens, the existence of at least one double bond categorizes the hydrocarbon as unsaturated. Hence, the first two statements are correct. Best regards.
Response:1816.6 joules
Clarification:refer to the attached image
The direction of the arrow indicates that the bond involving the chlorine atom and the fluorine atom is nonpolar. The fluorine atom pulls the electrons in the bond with greater strength, resulting in the chlorine atom being a little positive.
Explanation:
- The bond formed between chlorine and fluorine displays nonpolar characteristics because both atoms contribute an equal share of electrons within the bond. Examples such as H2, F2, and Cl2 illustrate this concept well.
- Both chlorine and fluorine are electronegative elements, yet fluorine resides above chlorine in the periodic table. Fluorine's position above chlorine gives it a somewhat higher electronegativity compared to chlorine. This explains why fluorine molecules attract electrons more efficiently than chlorine atoms, resulting in chlorine exhibiting a slight positive charge in bonds between Cl and F.
The answer is B. 45k. Human bodies contain approximately 60 to 70% water.
Assuming we have a 100g sample, the mass of each element is as follows:
C: 74 g
H: 7.4 g
N: 8.6 g
O: 10 g
Next, we calculate the moles of each by dividing the mass of each element by its molar mass:
C: (74 / 12) = 6.17
H: (7.4 / 1) = 7.4
N: (8.6 / 14) = 0.61
O: (10 / 16) = 0.625
Now, we take the smallest value to determine the ratio:
C: 10
H: 12
N: 1
O: 1
Thus, the empirical formula can be expressed as
C10H12NO
