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r-ruslan
10 days ago
12

When pure water and sodium chloride combine what do they create

Chemistry
You might be interested in
Enter the chemical equation 2H+(aq)+S2−(aq)→H2S(g). Express your answer as a chemical equation.
Anarel [2989]

Answer: The complete balanced chemical equation is,

2H^+(aq)+S^{2-}(aq)\rightarrow H_2S(aq)

Explanation:

A chemical equation represents the reactants on the left and the products on the right, separated by a right-pointing arrow indicating the reaction.

This representation includes the phases of the substances and uses subscripts and superscripts for numbers.

For the reaction given, the balanced chemical equation with phases is:

2H^+(aq)+S^{2-}(aq)\rightarrow H_2S(aq)

4 0
4 months ago
Read 2 more answers
Which has a lower freezing point ice or ice cream?
VMariaS [2998]
-0° is the freezing temperature of ice or ice cream.
8 0
4 months ago
Read 2 more answers
A food worker had safely cooled a large pot of soup to 70 F (21 C) with two hours. What temperature must the soup Reach in the f
lorasvet [2795]

After four hours of cooling, the soup reached a temperature of 140 F (or) 42 C.

Explanation:

A food worker allowed a cup of soup to cool for two hours,

step 1: The temperature attained in two hours is 70 F (or) 21 C

step 2: Consequently, in four hours, this doubles the value

Therefore, the temperature after four hours is 2(70)= 140 F (or) 2(21)= 42 C

4 0
4 months ago
NH4NO3, whose heat of solution is 25.7 kJ/mol, is one substance that can be used in cold pack. If the goal is to decrease the te
lorasvet [2795]

Answer:

To lower the temperature of the solution from 25.0°C to 5.0°C, it is necessary to use 35.2g of NH₄NO₃ for every 100.0g of water.

Explanation:

In order to cool down the solution, we need:

4.184 J/g°C × (5.0°C - 25.0°C) × (100.0g + X) = -Y

8368 J + 83.68 J/gX = Y (1)

Here, x represents the grams of NH₄NO₃ required, and Y represents the energy needed to remove heat.

Furthermore, the energy Y becomes:

Y = 25700 J/mol × \frac{1mol}{80,043g}X

Y = 321 J/g X (2)

Substituting (2) into (1)

8368 J + 83.68 J/g X = 321 J/g X

8363 J = 237.32 J/gX

X = 35.2g

This means 35.2g of NH₄NO₃ must be used for every 100.0g of water to achieve a temperature decrease from 25.0°C to 5.0°C.

I trust this information will be useful!

6 0
3 months ago
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