Answer:
1.5
Explanation:
It is given that:
Compound A and B originate from Sulfur + Oxygen.
Compound A:
6g sulfur + 5.99g Oxygen
Compound B:
8.6g sulfur + 12.88g oxygen
By comparing the ratios:
Compound A:
S: O = 6.00: 5.99
S/0 = 6.0g S / 5.99g O
Compound B:
S: O = 8.60: 12.88
S / O = 8.60g S / 12.88g O
The mass ratio of A and that of B
(6.0g S / 5.99g O) ÷ (8.60g S / 12.88g O)
(6.0 g S / 5.99g O) × (12.88g O / 8.60g S)
(6 × 12.88) / (5.99 × 8.60)
= 77.28 / 51.514
= 1.50017
= 1.5
CxHy + (x+0.25)O₂ → xCO₂ + 0.5yH₂O
m(CO₂)/{xM(CO₂)}=m(H₂O)/{0.5yM(H₂O)}
0.2845/{44.01x}=0.1451/{9.01y}
x/y=0.4=2:5
The empirical formula is C₂H₅.
Assuming we have a 100g sample, the mass of each element is as follows:
C: 74 g
H: 7.4 g
N: 8.6 g
O: 10 g
Next, we calculate the moles of each by dividing the mass of each element by its molar mass:
C: (74 / 12) = 6.17
H: (7.4 / 1) = 7.4
N: (8.6 / 14) = 0.61
O: (10 / 16) = 0.625
Now, we take the smallest value to determine the ratio:
C: 10
H: 12
N: 1
O: 1
Thus, the empirical formula can be expressed as
C10H12NO
