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earnstyle
14 days ago
10

The decay rate of a radioactive isotope can be increased by increasing the

Chemistry
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You are given a piece of paper and a match. The paper has a mass of 2.5 g. You then light the match and light the piece of paper
KiRa [2933]

Answer:

No

Explanation:

No. The demonstration in question does not infringe upon the conservation of mass.

The law of conservation of mass states that mass cannot be created or destroyed in a chemical reaction; however, mass can change from one form to another during the process.

In this instance, although the remnants of the paper weigh 0.5 g compared to the original weight of 2.5 g, the ashes and gases produced during combustion account for the missing mass of the paper.

The portion that has been burnt has transformed into other states. If the gas and ashes are adequately contained, they will correspond to the weight of the original paper when added to the remaining paper.

5 0
3 months ago
A 10.00 g sample of a soluble barium salt is treated with an excess of sodium sulfate to precipitate 11.21 g BaSO4 (M- 233.4). W
eduard [2782]

Answer:

The salt identified is barium chloride.

Explanation:

BaX_2++Na_2SO_4\rightarrow BaSO_4+2NaX

The moles of barium sulfate produced are \frac{11.21 g}{233.38 g/mol}=0.0480 mol

per the reaction, 1 mole of barium sulfate arises from 1 mole of BaX_2.

Therefore, 0.0480 moles result from:

\frac{1}{1}\times 0.0480 mol=0.0480 mol of BaX_2.

The quantity of BaX_2 used amounts to 10.00 g

Moles of BaX_2 = \frac{10.00 g}{\text{Molar mass}}[/tex]

0.0480 mol=\frac{10.00}{\text{Molar mass}}

The molar mass of BaX_2 is 208.33 g/mol

The closest answer to our calculation is BaCl_2=208.2 g/mol.

The correct identification is barium chloride, which has a molar mass of 208.2 g/mol.

8 0
3 months ago
A sample of an unknown substance has a mass of 0.158 kg. If 2,510.0 J of heat is required to heat the substance from 32.0°C to 6
alisha [2963]
Specific heat refers to the quantity of heat a material can absorb or release to alter its temperature by one degree Celsius. To calculate specific heat, we apply the equation for the heat absorbed by the system. The heat taken in or released by a system can be expressed by multiplying the mass of the substance by its specific heat capacity and the change in temperature. The formula is:
Heat = mC(T2-T1)
By substituting the provided values, we can find C, the specific heat of the substance.
2510 J = 0.158 kg (1000 g / 1 kg)(C)(61.0 - 32.0 °C) C = 0.5478 J/g°C
8 0
3 months ago
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A gas mixture called heliox, 6.11% o2 and 93.89% he by mass, is used in scuba tanks for descents more than 65 m below the surfac
Alekssandra [3086]
098.9 that’s what I think it is
3 0
2 months ago
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