Response:
Here's my calculation
Clarification:
Assume the starting concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.
We need to determine the initial concentration of HI.
1. We will need a chemical equation with concentrations, so let's compile all the information in one location.
H₂ + I₂ ⇌ 2HI
I/mol·L⁻¹: 0.30 0.15 x
2. Calculate the concentration of HI
![Q_{\text{c}} = \dfrac{\text{[HI]}^{2}} {\text{[H$_{2}$][I$_{2}$]}} =\dfrac{x^{2}}{0.30 \times 0.15} = 5.56\\\\x^{2} = 0.30 \times 0.15 \times 5.56 = 0.250\\x = \sqrt{0.250} = \textbf{0.50 mol/L}\\\text{The initial concentration of HI is $\large \boxed{\textbf{0.50 mol/L}}$}](https://tex.z-dn.net/?f=Q_%7B%5Ctext%7Bc%7D%7D%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BHI%5D%7D%5E%7B2%7D%7D%20%7B%5Ctext%7B%5BH%24_%7B2%7D%24%5D%5BI%24_%7B2%7D%24%5D%7D%7D%20%3D%5Cdfrac%7Bx%5E%7B2%7D%7D%7B0.30%20%5Ctimes%200.15%7D%20%3D%20%205.56%5C%5C%5C%5Cx%5E%7B2%7D%20%3D%200.30%20%5Ctimes%200.15%20%5Ctimes%205.56%20%3D%200.250%5C%5Cx%20%3D%20%5Csqrt%7B0.250%7D%20%3D%20%5Ctextbf%7B0.50%20mol%2FL%7D%5C%5C%5Ctext%7BThe%20initial%20concentration%20of%20HI%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B0.50%20mol%2FL%7D%7D%24%7D)
3. Plot the initial values
The graph below visualizes the initial concentrations as plotted on the vertical axis.
Answer:
A, B, and C
Explanation:
Indeed, atoms possess mass and serve as the fundamental building blocks of chemical elements. While matter is composed of atoms, these particles themselves do not occupy physical space.
Atoms consist mostly of void, which excludes them from the other responses.
This confirms that A, B, and C are the right choices.
The production mechanism for t-butyl alcohol proceeds as follows:
The reaction and corresponding rate law for isobutene adsorption on the Amberlyst-15 catalyst can be described by:
I + S ⇄ I * S 
where
represents the concentration of unoccupied sites
denotes the adsorption equilibrium constant
indicates the forward rate constant
are the concentrations of isobutene and the site occupied by isobutene
The equation for the adsorption of water (W) onto the Amberlyst-15 catalyst is outlined as:
W + S ⇄ W.S 
The surface reaction's rate law can be described as:
W.S + I.S ⇄ TBA. S + Sn 
The desorption rate law for TBA from the catalyst is as follows:
TBA. S ⇄ TBA + S 
The image included below illustrates the rest of the steps.
Science is ever-evolving with continuous discoveries; thus, the statement "it is stable and does not require modification due to new findings" is incorrect.