To calculate the moles of MgSO4.7H2O, we find the molar mass equals 246, thus moles = 32 / 246 = 0.13 moles. Upon heating, all 7 H2O from one molecule will evaporate. The total moles of H2O present amount to 7 x 0.13 = 0.91, and the mass of that H2O is 0.91 x 18 = 16.38g. Therefore, the mass of the anhydrous MgSO4 that remains is 32 - 16.38 = 15.62 g.
The answer is C: hydrogen bonds. Explanation: The surface tension and the capacity for heat storage in water are due to its hydrogen bonds. Water molecules have a strong attraction to one another through hydrogen bonding. These bonds are continuously forming and breaking within water molecules. The result of this hydrogen bonding is surface tension, which allows water to have a greater capacity for heat retention. Consequently, during the night, the temperature on Earth drops much faster than it does for water, as water gradually releases heat, helping maintain a moderate atmospheric temperature at night.
What precisely is being followed here?
The gravimetric factor for Ag2O within AgS amounts to 0.1078.
Answer:
B) Δ[C]/Δt = 3.60x10⁻² M⁻¹s⁻¹ [A] [B]
Explanation:
For the reaction A + B → C
The expression for the reaction's rate is:
Δ[C]/Δt = k [A] [B]
Utilizing the values for [A], [B], and Δ[C]/Δt, multiply [A] by [B] to acquire a value of X and consider Δ[C]/Δt as Y. The slope derived from this linear regression will yield k.
Therefore, the results you should have are:
y = 3.60x10⁻² X
Thus, the reaction's rate is:
B) Δ[C]/Δt = 3.60x10⁻² M⁻¹s⁻¹ [A] [B]
I hope this assists you!
