Response:
varn=n1+1ehvkT–1
Explanation:
This formula comes from Einstein's theory.
The half-life for substance A is determined to be 17.1 days. To explain: The half-life for substance B is noted to be 1.73 days. Let’s convert the 3 days elapsed time into terms of half-lives of B: 1.37 days equates to 1 half-life of B, implying 3 days translates to multiples of half-lives of B, specifically 2.19 half-lives. Consequently, the quantity of A in regard to B is expressed as follows: A = 4.04 B. For B, we can express the quantity after n half-lives as B0 / 2ⁿ. Hence, applying these relationships after 2.19 half-lives results in adjusting A similarly as A0 / 2ⁿ. Our derived equations lead us to relate the two expressions through substitutions where after cancelling A0, we derive the final calculation: 2ⁿ = 4.04 divided by 2^(2.19), which ultimately simplifies leading to 1 half-life of A totaling 17.1 days.
To address this issue, we apply the de Broglie equation written as:
λ = h/mv
where h equals 6.626×10⁻³⁴ J·s
Solving for m, we substitute for v, which is 46.9 m/s:
9.74 × 10⁻³⁵ m = 6.626×10⁻³⁴ J·s / (m)(46.9 m/s)
Thus, we find that m = 0.145kg
