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adelina 88
7 days ago
11

A toy car has a battery-powered fan attached to it such that the fan creates a constant force that is exerted on the car so that

it is propelled in the opposite direction in which the fan blows air. The car has a carriage that allows a student to attach objects of different masses, as shown above. The fan has only one speed setting. All frictional forces are considered to be negligible. Which of the following procedures could be used to determine how the mass of the fan-car-object system affects the acceleration of the system?
Physics
2 answers:
Softa [913]7 days ago
7 0

Response:

To find the mass of the system, weigh it with a balance, turn on the fan, measure how far the system travels in a set time using a stopwatch, and repeat for multiple trials with various objects.

Rationale:

serg [1.1K]7 days ago
4 0

Method point C can help analyze the influence of the combined mass of the fan-car-object system on its acceleration

Additional insights

According to Newton's 2nd law, the acceleration experienced by an object is directly proportional to the total force acting on it while being inversely proportional to its mass.

∑F = m. a

\large{\boxed{\bold{a=\frac{\sum F}{m}}}

Where: F = total force in N

m = mass in kg

a = acceleration in m/s²

Below are the possible procedures:

A). Weigh the total mass of the system with a scale, start the fan, measure how far the system travels in a specific time using a stopwatch, and conduct multiple trials with varying objects added.

B) Measure the mass with a balance, turn on the fan, utilize a meter stick and stopwatch to assess the starting and ending speeds, and repeat multiple trials with assorted objects on the carriage.

C) Gauge the mass using a balance, attach a spring scale to the car's rear, quantify the force needed to keep the system stationary, and repeat with various objects.

D) Weigh the mass using a balance, activate the fan, time how long the system moves until the fan battery depletes, then perform various trials with different objects.

Among these options, we select point C as it provides the force measurement (F) from the scale and the mass with a balance to determine the impact of mass on acceleration.

<pConsidering the formula, we understand that an increase in mass results in decreased acceleration.

Discover more

Newton's laws of motion

Keywords: system acceleration, toy car, fan

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Answer:

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1)After catching the ball, Sarah throws it back to Julie. However, Sarah throws it too hard so it is over Julie's head when it r
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Answer:

1)

v_{oy}=11.29\ m/s

2)

y=7.39\ m

Explanation:

Projectile Motion

When an object is projected near the surface of the Earth at an angle \theta to the horizontal, it follows a trajectory known as a parabola. The only force acting on it (ignoring wind resistance) is gravity, affecting the vertical axis.

The height of a projectile can be calculated using

\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}

where y_o represents the initial height from ground level, v_{oy} is the vertical component of the initial velocity, and t is the elapsed time.

The vertical speed component is expressed as

v_y=v_{oy}-gt

1) To proceed, we will determine the initial vertical velocity component since we lack sufficient data to calculate the absolute value of v_o.

The peak height is attained when v_y=0, which allows us to compute the time to reach that height.

v_{oy}-gt_m=0

Solving for t_m

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Thus, the maximum height reached is

\displaystyle y_m=y_o+\frac{v_{oy}^2}{2g}

We know this value is equal to 8 meters

\displaystyle y_o+\frac{v_{oy}^2}{2g}=8

Continuing with the calculations for v_{oy}

\displaystyle v_{oy}=\sqrt{2g(8-y_o)}

Substituting known values yields

\displaystyle v_{oy}=\sqrt{2(9.8)(8-1.5)}

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2) At t=1.505 seconds, the ball is positioned above Julie’s head; we can calculate

\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}

\displaystyle y=1.5+(11.29)(1.505)-\frac{9.8(1.505)^2}{2}

\displaystyle y=1.5\ m+16,991\ m-11.098\ m

y=7.39\ m

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Answer:

Explanation:

a) La fuerza neta que actúa sobre la caja en la dirección vertical es:

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b)

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