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melomori
1 month ago
4

A sample of helium gas occupies 12.9 L at 315 K and 1.20 atm.

Chemistry
1 answer:
Anarel [2.8K]1 month ago
5 0

Answer:

There are 0.6 moles of helium present.

Explanation:

Utilizing the ideal gas equation and applying the gas constant R = 0.082 l atm / K mol, we can determine the number of moles (n) from the equation:

PV=nRT --> n= PV/RT

n= 1.20 atm x 12.9 L / (0.082 l atm / K mol x 315 K)= 0.599303135 moles

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Marie and Calvin dissolved 10 grams of KNO3 in 100 grams of water at 25oC. Next they added 5 grams more. Calvin told Marie that
Alekssandra [3021]
Hi there! Calvin informed Marie that they could still incorporate solute until reaching 40 grams because the solution remained unsaturated. Unsaturated solutions denote situations where the solvent (water in this instance) can further dissolve more solute (here, KNO₃) considering the current pressure and temperature. This can be visually confirmed when additional solute does not lead to visible solid residues settling at the bottom of the flask, indicating that the dissolving rate surpasses the crystallization rate. Wishing you a pleasant day!
8 0
10 days ago
Does Na2 gas posses metallic character? Explain your answer..​
alisha [2934]

Clarification:

The Na2 molecules comprise atoms that are connected by a purely covalent bond since both atoms have the same electronegativity.

Metallic bonding only manifests when several atoms cluster together. Such aggregates may not tend to be stable, as larger masses of material typically exhibit greater stability thermodynamically. Therefore, they often merge until a significant metal chunk is formed.

In some ways, metallic bonding can be considered a variant of covalent bonding, but it is more communal—delocalized across numerous atoms—and electron deficient (there are more energy states than available electrons, which contributes to conductive traits). This implies that the term “metallic bond” might appear contradictory, akin to referring to a forest with a single tree.

Engage me in comments

4 0
1 month ago
6.74 g of the monoprotic acid KHP (MW = 204.2 g/mol) is dissolved into water. The sample is titrated with a 0.703 M solution of
eduard [2746]

Answer:

The volume of calcium hydroxide solution utilized is 0.0235 mL.

Explanation:

2KHP+Ca(OH)_2\rightarrow 2H_2O+Ca(KP)_2

Moles of KHP = \frac{6.74 g}{204.2 g/mol}=0.0330 mol

In accordance with the reaction, 2 moles of KHP react with 1 mole of calcium hydroxide, thus 0.0330 moles of KHP will react with;

\frac{1}{2}\times 0.0330 mol=0.01650 mol of calcium hydroxide

The molarity of calcium hydroxide solution = 0.703 M

Volume of calcium hydroxide solution = V

Molarity=\frac{Moles}{Volume(L)}

0.703 M=\frac{0.01650 M}{V}

V=\frac{0.01650 M}{0.703 M}=0.0235 mL

The volume of the calcium hydroxide solution utilized is 0.0235 mL.

4 0
21 day ago
a 5.00 L sample of helium expands to 12.0 L at which point the pressure is measured to be 0.720atm. what was the original pressu
lorasvet [2747]

Response:

The conclusion to your inquiry is Pressure 1 = 1.73 atm

Clarification:

Data provided

Volume 1 = 5 l

Pressure 1 =?

Volume 2 = 12 l

Pressure 2 = 0.72 atm

Procedure

To resolve this issue, Boyle's law is applied

                 Pressure 1 x Volume 1 = Pressure 2 x Volume 2

-Finding Pressure 1

                 Pressure 1 = Pressure 2 x Volume 2 / Volume 1

-Replace values

                 Pressure 1 = 0.72 x 12 / 5

-Calculating

                Pressure 1 = 8.64/5

-Final outcome

                 Pressure 1 = 1.73 atm

5 0
7 days ago
PLEASE HELP!! What direction do you predict the addition of a base to the solution containing bromophenol blue will drive the eq
Alekssandra [3021]

Answer:

Here is an explanation related to the same question.

Explanation:

  • According to Le Chatelier's principle , when the balance of a system is disturbed by external changes, the system adapts by altering the concentrations of its components in a manner that counteracts the disturbance, thus achieving a new stable equilibrium of concentration that differs from its previous state.
  • Bromothymol blue is known to function as a phenolic compound that operates effectively as an acid in water solutions. Because it is classified as a weak acid, it should not react rapidly, while simultaneously establishing equilibrium with its largely unrelated form.

For such a weak diprotic acid, the typical economic expression can indeed be articulated as:

    ⇒  H_2In_(aq)\rightleftharpoons In^{2-} +2H^+

  • It can be ultimately shown through Le Chatelier's concept that when a strong acid is introduced, the complete disorientation of either component influences an increase in the proton levels within the medium.
  • Likewise, it takes up protons throughout the medium leading to the breakdown of water each time a solution is introduced. Consequently, the concentration of particles in the medium decreases. To adjust for this change, the equilibrium shifts appropriately, thereby prompting further dissociation of the respective acid into its dianion in the presence of protons, aiming to nullify the initial disturbance.
4 0
11 days ago
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