Answer:
The ratios arranged in ascending order are; The ratio of the mass of Y to X in XY2 divided by the mass of Y to X in XY, The ratio of the mass of Y to X in XY3 divided by the mass of Y to X in XY, The ratio of the mass of Y to X in XY4 divided by the mass of Y to X in XY
1) Mass ratio = 3
2) Mass ratio = 2
3) Mass ratio = 4
Explanation:
Comprehensive calculations are displayed in the attachment.
Based on the equation:
ΔG = ΔH - TΔS = 0
It follows that ΔS = ΔH/T
So, ΔS = n*ΔHVap / Tvap
- where n represents the number of moles calculated as mass/molar mass
For a mass of 24.1 g
and a molar mass of 187.3764 g/mol
substituting gives:
∴ n = 24.1 / 187.3764g/mol
= 0.129 moles
The molar enthalpy of vaporization, ΔHvap, is 27.49 kJ/mol
The temperature in Kelvin, Tvap = 47.6 + 273 = 320.6 K
After substitution, we compute ΔS, the change in entropy:
∴ΔS = 0.129 mol * 27490 J/mol / 320.6 K
= 11 J/K
Answer:
The new gas pressure within the chamber registers at 1,093.75 mmHg
Explanation:
The Gay-Lussac Law establishes a relationship between a gas's pressure and temperature when volume remains constant. This principle asserts that gas pressure is directly tied to its temperature: as temperature increases, pressure rises, and conversely, as temperature falls, pressure also diminishes. Therefore, the Gay-Lussac law can be depicted mathematically as:

Given an initial and final state of gas, we can apply the following formula:

In this scenario:
- P1= 1560 mmHg
- T1= 445 K
- P2=?
- T2= 312 K
<psubstituting:>

Calculating:

P2=1,093.75 mmHg
The new gas pressure inside the chamber is 1,093.75 mmHg
</psubstituting:>
The enthalpy change associated with the precipitation reaction is 84 kJ/mole
Why?
The chemical equation for the reaction can be written as
AgNO₃(aq) + NaCl (aq) → AgCl(s) + NaNO₃(aq)
To determine the enthalpy change, the following equation applies

To calculate the heat (Q):

Next, we need to calculate the number of moles involved in the reaction (n):
![n=[AgNO_3]*v(L)=(0.1M)*(0.05L)=0.005moles](https://tex.z-dn.net/?f=n%3D%5BAgNO_3%5D%2Av%28L%29%3D%280.1M%29%2A%280.05L%29%3D0.005moles)
With these two values, we can substitute them into the first equation:

Have a great day!