A 0.0200 M NaCl solution was formed when 38.0 grams of NaCl was dissolved in enough water. What was the total volume of the solu

Question

Rina8888

3 months ago

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A 0.0200 M NaCl solution was formed when 38.0 grams of NaCl was dissolved in enough water. What was the total volume of the solu

tion formed?

Chemistry

2 answers:

VMariaS [2.9K] · Answer 1 · 2026-03-02T07:29:23+03:00

Answer: The total volume of the solution produced is 32.5 L.

Explanation:

Molarity denotes the quantity of solute included in 1 liter of solution. The formula for calculating molarity is as follows:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given values:

Molarity of the solution = 0.02 mol/L

Mass of NaCl = 38 grams

Molar mass of NaCl = 58.5 g/mol

Substituting these values into the equation results in:

$0.02mol=\frac{38g}{58.5g/mol\times V_s}\\\\\text{Volume of the soltion}=32.5L$

Therefore, the total volume of the solution produced is 32.5 L.

Tems11 [2.7K] · Answer 2 · 2026-03-02T07:26:04+03:00

Start by determining the number of moles, which is obtained by dividing 38 grams by the molar mass of 58.43 g/mol. This calculation yields 0.65 moles. The concentration is calculated by dividing the number of moles by the volume in liters. Using this formula, we can derive the total volume by dividing the number of moles by the concentration. Thus, 0.65 moles divided by 0.02M (mol/L) results in a total volume of 32.5 L.