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goldenfox
3 days ago
14

A gold wire that is 1.8 mm in diameter and 15 cm long carries a current of 260 mA. How many electrons per second pass a given cr

oss-section of the wire? (e=1.60×10−19 C) A gold wire that is 1.8 mm in diameter and 15 cm long carries a current of 260 mA. How many electrons per second pass a given cross-section of the wire? ( C) 1.5×1023 1.6×1018 6.3×1015 1.6×1017 3.7×1015
Physics
1 answer:
kicyunya [1K]3 days ago
3 0

Answer:

(1.6 × 10¹⁸) /s

Explanation:

The current in a wire is calculated using the formula:

I = (Q/t)

where Q represents the total charge of the electrons in the wire

and t denotes time.

Moreover, Q can be expressed as nq

where n is the number of electrons present in the wire

and q is the charge of a single electron, 1.602 × 10⁻¹⁹ C.

This leads us to the equation I = nq/t.

Thus, (n/t) = (I/q) describes the number of electrons flowing per second through a cross-section.

Inserting our current, I = 260 mA or 0.26 A, along with q = 1.6 × 10⁻¹⁹ C, yields:

(n/t) = (0.26/(1.602×10⁻¹⁹)) = (1.62 × 10¹⁸) /s = (1.60 × 10¹⁸) /s

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