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deff fn
1 month ago
5

Every Methane molecule looks different. True or false?

Chemistry
1 answer:
Tems11 [2.7K]1 month ago
8 0

Answer:

False

Explanation:

Molecules of a single substance consist of identical types of atoms and appear exactly the same.

Therefore, if I possess two methane molecules that encompass precisely the same carbon and hydrogen atoms, they will be indistinguishable in terms of appearance.

Thus, all methane molecules are essentially identical as long as they are formed from the same isotopic atoms of hydrogen and carbon.

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Arrange the sublevels in ascending order by the number of electrons they can contain. p sublevel s sublevel d sublevel f subleve
eduard [2782]

The electronic configuration of an atom details how electrons are organized across various shells and sublevels.

There are four categories of sublevels: s, p, d, and f. Each of these sublevels contains orbitals, which are regions with a high likelihood of containing an electron, with each orbital capable of holding a maximum of 2 electrons.

As a result,

s-sublevel possesses 1 orbital, allowing for a maximum of 2 electrons.

p-sublevel has 3 orbitals, accommodating a maximum of 6 electrons.

d-sublevel encompasses 5 orbitals, permitting a maximum of 10 electrons.

f-sublevel includes 7 orbitals, with a maximum of 14 electrons.

Therefore, the ascending order of sublevels based on the maximum number of electrons they can hold is:

s < p < d < f

3 0
1 month ago
Read 2 more answers
6.74 g of the monoprotic acid KHP (MW = 204.2 g/mol) is dissolved into water. The sample is titrated with a 0.703 M solution of
eduard [2782]

Answer:

The volume of calcium hydroxide solution utilized is 0.0235 mL.

Explanation:

2KHP+Ca(OH)_2\rightarrow 2H_2O+Ca(KP)_2

Moles of KHP = \frac{6.74 g}{204.2 g/mol}=0.0330 mol

In accordance with the reaction, 2 moles of KHP react with 1 mole of calcium hydroxide, thus 0.0330 moles of KHP will react with;

\frac{1}{2}\times 0.0330 mol=0.01650 mol of calcium hydroxide

The molarity of calcium hydroxide solution = 0.703 M

Volume of calcium hydroxide solution = V

Molarity=\frac{Moles}{Volume(L)}

0.703 M=\frac{0.01650 M}{V}

V=\frac{0.01650 M}{0.703 M}=0.0235 mL

The volume of the calcium hydroxide solution utilized is 0.0235 mL.

4 0
27 days ago
Rank the following chemical species from lowest absolute entropy (So) (1) to highest absolute entropy (5) at 298 K?
lorasvet [2795]

Answer:

Can you rank the following chemical substances in order of their absolute entropies (So) from lowest (1) to highest (5) at a temperature of 298 K?

a. Al (s)

b. H2O (l)

c. HCN (g)

d. CH3COOH (l)

e. C2H6 (g)

Explanation:

Entropy quantifies the level of disorder within a system.

In solids, the entropy is significantly lower compared to liquids and gases.

The typical order of entropy is:

solids < liquids < gases

In the substances listed, liquid water notably exhibits strong intermolecular hydrogen bonding.

This results in water having comparatively lower entropy.

Next in line is acetic acid.

Among the gaseous components, ethane has higher entropy than HCN due to its weaker intermolecular interactions.

HCN involves some hydrogen bonding.

Thus, the order of entropy is:

Al(s) < CH3COOH (l) < H2O(l) < HCN(g) < C2H6(g)

7 0
1 month ago
Identify the oxidized substance, the reduced substance, the oxidizing agent, and the reducing agent in the redox reaction. Cu(s)
alisha [2963]

Answer: Copper is being oxidized and acts as a reducing agent. In contrast, silver is being reduced, functioning as the oxidizing agent.

Explanation:

An oxidation reaction involves the loss of electrons by an atom. Here, the oxidation state of the atom rises.

X\rightarrow X^{n+}+ne^-

Conversely, a reduction reaction is characterized by an atom gaining electrons, resulting in a decrease in its oxidation state.

X^{n+}+ne^-\rightarrow X

Oxidizing agents are those that facilitate the oxidation of another substance while themselves being reduced. These substances participate in reduction reactions.

Reducing agentsare defined as those that reduce other substances while undergoing oxidation themselves. They also take part in reduction reactions.

In the provided chemical reaction:

Cu(s)+2AgNO_3(aq.)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq.)

The associated half-reactions for the above process are:

Oxidation half reaction:  Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-

Reduction half reaction:  2Ag^+(aq.)+2e^-\rightarrow 2Ag(s)

From the reactions outlined, copper is losing electrons. Consequently, it is oxidized and regarded as a reducing agent.

Silver is acquiring electrons, thus it is being reduced and viewed as an oxidizing agent.

4 0
1 month ago
At 1.01 bar, how many moles of CO2 are released by raising the temperature of 1 litre of water from 20∘C to 25∘C
VMariaS [2998]

Answer: 0.0007 moles of CO_2 are released when the temperature rises.

Explanation:

To determine the moles, we utilize the ideal gas law, as follows:

PV=nRT

where,

P = gas pressure = 1.01 bar

V = gas volume = 1L

R = gas constant = 0.08314\text{ L bar }mol^{-1}K^{-1}

  • Calculated moles at T = 20° C

The gas temperature = 20° C = (273 + 20)K = 293K

Substituting values into the equation gives:

1.01bar\times 1L=n_1\times 0.0814\text{ L bar }mol^{-1}K^{-1}\times 293K\\n_1=0.04146moles

  • Calculated moles at T = 25° C

The gas temperature = 25° C = (273 + 25)K = 298K

Substituting values into the equation gives:

1.01bar\times 1L=n_2\times 0.0814\text{ L bar }mol^{-1}K^{-1}\times 298K\\n_2=0.04076moles

  • Released moles = n_1-n_2=0.04146-0.04076=0.0007moles

Therefore, 0.0007 moles of CO_2 are released when the temperature increases from 20° C to 25° C.

5 0
1 month ago
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