The Thompson analogy titled "The Carpet-Seed Children Analogy" attempts to deal with the issue of failed ____________________(A)

To address this issue, we can apply the following equation:

w = (mass of solute) / (mass of solution)

w - percentage

It is important to note that the mass of the solution is the sum of the mass of the solute and the mass of the water.

<span>w = mass CaCl2/(mass of water + mass of CaCl2)
</span>
mass of water = x

0.35 = 36 / (x + 36)

0.35 × (x + 36) = 36

0.35x + 12.6 = 36

0.35x = 23.4

x = 66.86 g of water is required

Utilize the principle that pH = log { 1 / [H+] }. Designate x as the hydrogen ion concentration of one solution and 100x for the other. The pH of the solution with hydrogen concentration x is pH1 = log {1 / x}. For the solution with 100x concentration, it is pH2 = log {1 / 100x}. Now, you find pH2 - pH1 = log {1/x} - log {1 / 100x}. By applying the properties of logarithms, you arrive at pH2 - pH1 = log {1/x} - log {1/x} - log {1/100} = - (-2) = 2. Thus, the conclusion is that if one solution contains 100 times more hydrogen ions than another, the difference in pH units between the two solutions is 2<span>.</span>

Answer:

A total of 2667 tires are required to satisfy the annual power needs of ten homes.

Explanation:

According to the Second Law of Thermodynamics, not all energy produced when tires are incinerated can be effectively used due to losses associated with finite temperature differences. The energy obtainable from a tire when burned, measured in kilowatt-hours (), can be calculated using the efficiency definition:

Where:

- Efficiency, which is dimensionless.

- Energy released from burning, measured in kilowatt-hours.

Taking into account and , the yearly energy yield from a tire amounts to:

Thus, the number of tires necessary to meet the electricity demand of ten homes for one year is:

A total of 2667 tires are necessary to satisfy the annual power needs of ten homes.

In the reaction: <span>caco3(s) → cao(s) + co2(g), it is evident that
1 mol (which is 100 g) of CaCO3 yields 1 mol (which is 44 g) of CO2
Now, the molarity of CaCO3 present in the reaction system is
</span>= 
=  = 0.45 mol

Thus, 0.45 mol of CaCO3 leads to the formation of 0.45 mol of CO2.

According to the ideal gas equation, we have PV = nRT
V = .
Considering P = 645 torr = 0.8487 atm (because 1 atm = 760 torr)
In that case, V = 

= 34.8 l

Answer:

Refer to the explanation.

Explanation:

Formation reactions involve the creation of one mole of a compound from its elements in their standard states.

NaBr (s)

The equation for the standard formation is

Na (s) + (1/2)Br₂ (g) → NaBr (s)

As per appendix C, the standard heat of formation for NaBr(s) is

ΔH∘f = -359.8 kJ/mol.

SO₃ (g)

The equation for the standard formation is

S (s) + (3/2) O₂ (g) → SO₃ (g)

<paccording to="" appendix="" c="" the="" standard="" heat="" of="" formation="" for="" so="" is="">

ΔH∘f = -395.2 kJ/mol.

Pb(NO₃)₂ (s)

The equation for the standard formation is

Pb (s) + N₂ (g) + 3O₂ (g) → Pb(NO₃)₂ (s)

According to appendix C, the standard heat of formation for Pb(NO₃)₂(s) is

ΔH∘f = -451.9 kJ/mol.

I hope this is helpful!

</paccording>