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Usimov
1 month ago
11

Two bricks are resting on the edge of the lab table. Shirley Sheshort stands on her toes and spots the two bricks. She acquires

an intense desire to know which of the two bricks are most massive. Since Shirley is vertically challenged, she is unable to reach high enough and lift the bricks; she can however reach high enough to give the bricks a push. Discuss how the process of pushing the bricks will allow Shirley to determine which of the two bricks is most massive. What difference will Shirley observe and how can this observation lead to the necessary conclusion?​
Physics
1 answer:
Keith_Richards [3.2K]1 month ago
4 0
Applying the formula of force equals mass times acceleration, and considering acceleration approximated as g at 10 m/s², the brick possessing the greater mass will hit the ground first due to its superior force that counteracts resistive forces like air resistance.
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An object is at rest on the ground. The object experiences a downward gravitational force from Earth. Which of the following pre
Yuliya22 [3333]

Answer:

A) and B) are valid.

Explanation:

When an object remains at rest, it is indicative that no net force acts upon it.

The downward gravitational force from Earth must be counterbalanced by an upward force of equal magnitude in order to maintain rest.

This upward force is provided by the normal force, which adjusts to satisfy Newton’s 2nd Law and is always perpendicular to the surface supporting the object (in this instance, the ground).

At the molecular level, this normal force comes from the ground's bonded molecules acting like tiny springs, compressed by the object’s molecules, providing an upward restorative force.

Thus, statements A) and B) are true.

6 0
2 months ago
Read 2 more answers
Chromatic aberration comes from the fact that different wavelengths of light travel at different speeds through the material of
Yuliya22 [3333]

Response:

 y_red / y_blue = 1.11

Clarification:

To determine the image for each wavelength, we'll utilize the lens maker's equation

         1 /f = 1 /o + 1 /i

Where f signifies the focal length, o represents the object distance, and i indicates the image distance

For red light

           1 / i = 1 / f - 1 / o

           1 / i_red = 1 / f_red - 1 / o

           1 / i_red = 1 / 19.57 - 1/30

           1 / i_red = 1.776 10-2

           i_red = 56.29 cm

For blue light

            1 / i_blue = 1 / f_blue - 1 / o

            1 / i_blue = 1 / 18.87 - 1/30

            1 / i_blue = 1.966 10-2

            i_blue = 50.863 cm

Next, we will compute the magnification ratio

             m = y ’/ h = - i / o

             y ’= - h i / o

For red light

            y_red ’= - 5 56.29 / 30

            y_red ’= - 9.3816 cm

For blue light

            y_blue ’= 5 50.863 / 30

            y_blue ’= - 8.47716 cm

The ratio of the heights of both images is

            y_red ’/ y_blue’ = 9.3816 / 8.47716

            y_red / y_blue = 1.107

            y_red / y_blue = 1.11

5 0
1 month ago
The two sides of the DNA double helix are connected by pairs of bases (adenine, thymine, cytosine, and guanine). Because of the
kicyunya [3294]

Answer:

Explanation:

An image of the bond resulting from the search is attached.

Consider the force directed towards thymine as negative.

For the O-H-N combination:

The resulting force from this combination is:

F=-F_{OH}+F_{ON}\\\\=\frac{Ke^2}{r^2}+\frac{Ke^2}{r'^2}\\\\=Ke^2(\frac{-1}{r^2}+\frac{1}{r'^2})\\\\=(9.0\times 10^9Nm^2/kg^2)(1.6\times 10^{-19}C)^2[\frac{1}{[(0.280-0.110)\times 10^{-9}m]^2}+\frac{1}{0.280\times 10^{-9}m)^2}]\\\\=-5.03354\times 10^{-9}N

In the case of the N-H-N combination:

The total force acting from this combination is:

F'=F_{NN}-F_{HN}\\\\=\frac{Ke^2}{r^2}-\frac{Ke^2}{r'^2}\\\\=Ke^2(\frac{-1}{r^2}+\frac{1}{r'^2})\\\\=(9.0\times 10^9Nm^2/kg^2)(1.6\times 10^{-19}C)^2[\frac{1}{[0.300\times 10^{-9}m]^2}-\frac{1}{((0300-0..110)\times 10^{-9})m)^2}]\\\\=-3.822\times 10^{-9}N

The force that thymine applies on adenine is:

F_{net}=F+F'\\\\=-5.03354\times 10^{-9}N-3.822\times 10^{-9}N\\\\=-8.8558\times 10^{-9}N

When rounded to three significant figures, the net force is 8.86\times 10^{-9}N

b)

The negative value indicates that the force is attractive, as it is aimed towards thymi.

c)

The force acting on the electron due to the proton is:

F=\frac{Ke^2}{r^2}\\\\=\frac{(9.0\times 10^9Nm^2/C^2)(1.6\times 10^{-9}C)^2}{(5.29\times 10^{-11}m)^2}\\\\=8.233\times 10^{-8}N

Since the electron and proton carry opposite charges, the force on the electron points towards the proton.

d)

The ratio of the above forces is:

\frac{F}{F_{net}}=\frac{8.233\times 10^{-8}N}{8.233\times 10^{-8}N}\\\\=9.3

Therefore, the bonding strength of the electron in the hydrogen atom is 9.3 times greater than the bonding force between adenine and thymine molecules.

5 0
2 months ago
1. A U.S. manufacturer wants to sell computer equipment to companies in Honduras. Because the U.S. government limits trade with
Ostrovityanka [3204]
If the U.S. government prohibits the manufacturer from exporting their products to Honduras, the manufacturer will forfeit the non-refundable application fee of $2,700. Additionally, due to the restrictions on trade with Honduras, the manufacturer must secure an export license from the Department of Commerce, potentially leading to reduced demand for U.S. goods. Furthermore, the total value of product exports must reach at least $10,800 while the license is active to justify the application and licensing fees.
3 0
1 month ago
Suggest one reason why the bricklayer needs a higher energy diet than the computer operator
Sav [3153]

Answer:

He requires more because his level of physical activity is higher, implying he exerts his body more and needs additional energy compared to someone who is sedentary in an office. The computer operator would not require as much energy as the bricklayer.

7 0
28 days ago
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