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spayn
25 days ago
6

On a snowy day, when the coefficient of friction μs between a car’s tires and the road is 0.50, the maximum speed that the car c

an go around a curve is 20 mph. What is the maximum speed at which the car can take the same curve on a sunny day when μs=1.0?

Physics
2 answers:
Maru [3.3K]25 days ago
8 0
On a sunny day, the speed maximum for the car on the curve is approximately 28 mph. Further elaboration includes how centripetal acceleration can be expressed using the formula: a = Centripetal Acceleration (m/s²), v = Tangential Speed of the Particle (m/s), and R = Radius of Circular Motion (m). Similarly, centripetal force is represented as: F = Centripetal Force (m/s²), m = mass of the Particle (kg), and v = Tangential Speed of the Particle (m/s) with R as the curve radius. In tackling this problem, we note that on a snowy day, the friction coefficient μs₁ is 0.50, coupled with a maximum speed v₁ of 20 mph, while on a sunny day, μs₂ is at 1.0.
kicyunya [3.2K]25 days ago
7 0
The result is 28.1 mph. The friction force exerted on the car contributes the needed centripetal force that maintains the car in its circular path. We represent this with the equation: (1). The variables involved include the coefficient of friction, m the mass of the car, g = 9.8 m/s² for gravity acceleration, v for maximum speed, and r as the curve radius. For the curve on a snowy day, where the friction coefficient is at 0.50, the maximum speed recorded was 20 mph. Using that value, we can rearrange our equation to uncover the maximum speed for a sunny day at μs = 1.0, revealing the answer.
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Answer:

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15 days ago
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Answer:

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