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zmey
27 days ago
14

A balloon was filled to a volume of 2.50 l when the temperature was 30.0∘c. What would the volume become if the temperature drop

ped to 11.0∘c.
Physics
1 answer:
Keith_Richards [2.2K]27 days ago
4 0

Answer:

2.34 L

Explanation:

Assuming the pressure within the balloon is held steady, we can apply Charle's law which states that for a gas at constant pressure, the ratio of its volume to temperature remains unchanged:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

In our scenario:

V_1 = 2.50 L is the initial volume

V_2 is the final volume

T_1 = 30.0^{\circ}C+273 = 303 K is the starting temperature

T_2 = 11.0^{\circ}C+273 = 284 K is the concluding temperature

By plugging values into the equation and resolving for V2, we can calculate the final volume:

V_2 = \frac{V_1 T_2}{T_1}=\frac{(2.50 L)(284 K)}{303 K}=2.34 L

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