How many kilowatt-hours of electricity are used to produce 4.50 kg of magnesium in the electrolysis of molten mgcl2 with an appl

Answer:

V = 56.816 cm³

Explanation:

It is given that

The recorded value of the cylinder is 54.5 cm³

The measurement error percentage for the volume is 4.25%

Our goal is to determine the actual volume of the cylinder.

First, we calculate the error in the volume determination as follows:

It mentions in the problem that the teacher indicated that her estimation was 4.25% higher than the actual volume. Therefore,

Total volume = 54.5 + 2.316 = 56.816 cm³

Thus, the true volume of the cylinder amounts to 56.816 cm³.

Answer:

The yield percentage is 95.0%.

Explanation:

Step 1: Provided data

Amount of Ba(NO3)2 = 0.3 moles

Amount of Na3PO4 = 0.25 moles

Amount of Ba3(PO4)2 = 0.095 moles

Step 2: Balanced chemical equation

3 Ba(NO3)2 + 2 Na3PO4 → 6 NaNO3 + Ba3(PO4)2

Step 3: Identify the limiting reagent

To convert 3 moles of Ba(NO3)2 into 6 moles of NaNO3 and 1 mole of Ba3(PO4)2, 2 moles of Na3PO4 are required.

Ba(NO3)2 is the limiting reactant and will be fully used up (0.3 moles). Na3PO4 is in surplus, reacting with only 0.20 moles.

It will leave a residual amount of 0.25 - 0.20 = 0.05 moles.

Step 4: Calculate the moles of Ba3(PO4)2 produced

For 3 moles of Ba(NO3)2, the yield will be 0.3/3 = 0.1 moles of Ba3(PO4)2.

Step 5: Compute the percent yield

% yield = (actual yield / theoretical yield) * 100%

% yield = (0.095 / 0.1) * 100%

% yield = 95.0%.

The yield percentage is 95.0%.

422,256 is equated to 2,000

42,256 equals 200

The total combined would be 2,200 (if that is also what you required)