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Montano1993
2 days ago
14

Two identical wheels, wheel 1 and wheel 2, initially at rest begin to rotate with constant angular accelerations α. After rotati

ng through the same angular displacement, Δθ0, the angular velocity of wheel 1 is ω1 and the angular velocity of wheel 2 is ω2=3ω1. How does the angular acceleration of wheel 2, α2, compare to the angular acceleration of wheel 1, α1?a. a2 = a1b. a2 = a1/3c. a2 = 3a1d. a2 = 9a1

Physics
2 answers:
Maru [2.9K]2 days ago
6 0
a2 = 3a1.
ValentinkaMS [3K]2 days ago
5 0
d. a2 = 9a1.
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A displacement vector points in a direction of θ = 23° left of the positive y-axis. The magnitude of this vector is D = 155 m. R
Keith_Richards [2877]

Answer:

Dₓ = -155 sin 23° i + 0 j

Explanation:

The accompanying diagram illustrates the vector.

According to the diagram,

The vector D has an x-component (or horizontal component) expressed as -D sinθ i. Specifically,

Dₓ = -D sin θ i   [The negative sign indicates that D is directed along the negative x-axis]

Where;

D = magnitude of D = 155m

θ = angle of D = 23°

Consequently;

Dₓ = -155 sin 23° i

Since Dₓ signifies the x component, its unit vector, j component holds a value of 0.

<pthus d="" can="" be="" formulated="" in="" terms="" of="" and="" the="" unit="" vectors="" i="" j="" as="" follows="">

Dₓ = -155 sin 23° i + 0 j

</pthus>
3 0
1 month ago
Gamma rays may be used to kill pathogens in ground beef. One irradiation facility uses a 60Co source that has an activity of 1.0
ValentinkaMS [3076]

Answer:

Explanation:

C_i=3.7\times 10^{16} \,decays/sec

The energy from gamma rays generated by ore decay is

(1.17+1.33)MeV=2.50MeV

The energy from gamma rays created per second is

(2.5\times 3.7\times 10^{16})MeV

Activity

1 \times 10^6c

The total energy of gamma rays produced in one second is

(2.5 \times 3.7 \times 10^{16} \times 10^6)MeV

E represents the energy of gamma rays generated in one hour is

(2.5\times 3.7\times 10^{10}\times 60 \times 60)MeV

Gamma ray energy absorbed by meat = 30% (in 1 hour) of E is 0.3E

The dosage necessary to eliminate pathogens = 4000Gy=4000J/kg

The mass of meat that can be processed every hour is

\frac{0.3E/hr}{4000J/kg}\\\\E=(2.5\times 3.7\times 10^{10}\times 60 \times 60)MeV\\\\=333\times 10^{18}MeV\\\\eV=1.6\times 10^{-19}\\\\E=53.3J

The total meat produced =\frac{0.3\times 53.3}{4000}=3.996\times 10^{-3}

4 0
1 month ago
A positive point charge q is placed at the center of an uncharged metal sphere insulated from the ground. The outside of the sph
Softa [2661]
B. The charge on A is -q; B has no charge. Given that a positive charge is situated at the center of an uncharged metallic sphere which is insulated and disconnected from the ground, a negative charge (-q) will appear on the inner surface A of the sphere. Should the exterior surface B be grounded, it will become neutral, resulting in no charge remaining on surface B.
4 0
13 days ago
A rock is dropped from the top of a tall building. The rock's displacement in the last second before it hits the ground is 46 %
inna [2723]

The height measures 69.68 m

Explanation:

Given data

Before striking the ground =  46 % of the total distance

To establish

the height

Solution

We know here acceleration and displacement, which is

d = (0.5)gt²..............1

Here d is the distance, g is the acceleration, and t is time

So, when an object falls it will be

h = 4.9 t²....................2

For the first part of the inquiry

The falling objects account for

54 % of the total distance

0.54 h = 4.9 (t-1)²...................3

Thus,

Now we possess two equations with unknown variables

We can equate both equations

The first equation already solves for h

Substituting h in the second equation allows us to find t

0.54 × 4.9 t² = 4.9 (t-1)²  

t = 0.576 s and  3.771 s

We choose here 3.771 s since 0.576 s is negligible; the distance covered in the last second before it impacts the ground is 46 % of the entire fall.

Thus, selecting t = 3.771 s

Then h from equation 2

h = 4.9 t²

h = 4.9 (3.771)²

h =  69.68 m

Thus, the height is 69.68 m

6 0
16 days ago
Which statement is always false for athletes participating in team sports?
Softa [2661]
Which statement can never be true for athletes in team sports? The statement that is always false among the listed options for team sports athletes is choice C) Conflict resolution indicates a lack of sportsmanship. The other statements are valid in the context of team sports.
3 0
15 days ago
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