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stich3
1 month ago
9

Which quantity gives the best indication of the relative strength of the hydrogen bonds between the molecules in liquid hydrogen

halides?
A: bond dissociation energies
B: enthalpy changes of formation
C: enthalpy changes of solution
D: enthalpy changes of vaporization


answer is D but how
Chemistry
1 answer:
castortr0y [3K]1 month ago
3 0
The hydrogen bonds represent a type of intermolecular force.

This means it describes the attraction between molecules, which tends to keep them close to one another quite firmly.


Vaporization refers to the transition from a liquid state, where molecules are in close proximity, to a gaseous state, where molecules are more spread out. To achieve this separation, the robust hydrogen bonds must be broken, necessitating more energy compared to similar substances lacking hydrogen bonds.

This results in significantly high values for the enthalpy of vaporization in compounds characterized by hydrogen bonds (such as hydrogen halides).


Thus, this leads to option D being the correct choice among the provided answers. The enthalpy of vaporization serves as the most reliable indicator of the relative strength of hydrogen bonds.

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At 400K both compounds are gases. At this temperature, which compound, CH4(g) or CCl4(g) , behaves more like an ideal gas
Alekssandra [3086]

Answer:

CH4

Explanation:

The ideal behavior of gases generally depends on the strength of intermolecular forces between gas molecules and whether polar bonds are present.

In the case of CCl4, polar bonds exist along with the more electronegative chlorine atom, leading to stronger intermolecular forces at 400K, as opposed to CH4 which contains only non-polar bonds.

Thus, at 400K, CH4 behaves more like an ideal gas compared to CCl4.

6 0
2 months ago
What volume of co2 gas at 645 torr and 800. k could be produced by the decomposition of 45.0 g of caco3? caco3(s) → cao(s) + co2
KiRa [2933]
In the reaction: <span>caco3(s) → cao(s) + co2(g), it is evident that
1 mol (which is 100 g) of CaCO3 yields 1 mol (which is 44 g) of CO2
Now, the molarity of CaCO3 present in the reaction system is
</span>= \frac{weight of CaCO3 (g)}{gram molecular weight}
= \frac{45}{100} = 0.45 mol

Thus, 0.45 mol of CaCO3 leads to the formation of 0.45 mol of CO2.

According to the ideal gas equation, we have PV = nRT
V = \frac{nRT}{P}.
Considering P = 645 torr = 0.8487 atm (because 1 atm = 760 torr)
In that case, V = \frac{0.45 X 0.08206 X 800}{0.8487}

= 34.8 l
5 0
1 month ago
What is the emperical formula for a compound containing 68.3% lead, 10.6% sulfur, and the remainder oxygen? a. Pb2SO4 b. PbSO3 c
Tems11 [2777]

Solution:

The molecular formula is PbSO₄, indicating lead sulfate

Option c.

Explanation:

The percentage makeup shows that in 100 g of this compound, there are:

68.3 g of Pb, 10.6 g of S, and (100 - 68.3 - 10.6) = 21.1 g of O

To find the moles of each element, we divide by their molar masses:

68.3 g Pb / 207.2 g/mol = 0.329 moles Pb

10.6 g S / 32.06 g/mol = 0.331 moles S

21.1 g O / 16 g/mol = 1.32 moles O

Next, we find the mole ratio by dividing each by the smallest number of moles:

0.329 / 0.329 = 1 Pb

0.331 / 0.329 = 1 S

1.32 / 0.329 = 4 O

Thus, the molecular formula is PbSO₄, representing lead sulfate.

8 0
2 months ago
Read 2 more answers
How many grams of NaC2H3O2 are needed to prepare 350. mL of a 2.75 M solution? (molar mass of
eduard [2782]

Answer:

78.96 g of NaC2H3O2

Explanation:

The following information is provided:

  • The solution's volume is 350 mL
  • The solution's molarity is 2.75 M
  • The molar mass of NaC2H3O2 is 82.04 g/mol

We need to find the mass of the solute:

First, we calculate the number of moles:

Moles = Molarity × Volume

Thus;

Moles of solute = 2.75 M × 0.350 L

                        = 0.9625 moles

Next, we find the mass:

Mass = Moles × Molar mass

        = 0.9625 moles × 82.04 g/mol

        = 78.9635 g

      = 78.96 g

Therefore, the amount of NaC2H3O2 required is 78.96 g

4 0
2 months ago
Which statement explains why sulfur is classified as a Group 16 element?
Tems11 [2777]

Answer: The correct option is (1).

Explanation:

Group 16 is the third-from-last column in the periodic table and is known as the oxygen family.

Members of this group include oxygen, sulfur, selenium, tellurium, and polonium.

Elements in Group 16 have 6 valence electrons in their outermost shell.

The electronic configuration of sulfur is 1s^22s^22p^63s^23p^4.

Because sulfur belongs to Group 16, it has 6 valence electrons.

3 0
1 month ago
Read 2 more answers
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