The reaction between methanol and oxygen gas produces water vapor and carbon dioxide. 2CH3OH(l)+3O2(g)⟶4H2O(g)+2CO2(g) Three sea
1 answer:
Answer:
The flask yielding the greatest amount of product is the second flask.
The water molecules produced are
Explanation:
From the prompt we learn that
The chemical reaction is
2CH3OH(l) + 3O2(g)⟶4H2O(g)+2CO2(g)
The first flask contains 3 molecules of C H 3 O H and 3 molecules of O 2
The second flask has 1 molecule of C H 3 O H and 6 molecules of O 2.
The third flask consists of 4 molecules of C H 3 O H and 2 molecules of O 2.
Analyzing the three flasks, it's evident that the flask producing the most considerable total product is the second one.
According to the balanced equation, 2 moles of C H 3 O H react with 3 moles of oxygen, making O 2 the limiting reagent.
Generally, one mole of any substance is of that substance.
Here, represents Avogadro's number valued at
.
As seen in the balanced equation, 3 moles of O 2 (3 * molecules of O 2) yield 4 moles of H2O (4 *
Thus, 6 molecules of O 2 would generate X molecules of H 2 O.
So
=>
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84.34 grams of iron (III) chloride is the maximum produced since iron is the limiting reagent, and chlorine gas is in excess.
Explanation:
Balanced equation:
2 Fe + 3 Cl2 → 2 FeCl3
DATA PROVIDED:
iron = atoms
mass of chlorine = 67.2 liters
mass of FeCl3 =?
The number of moles of iron will be calculated as
number of moles =
number of moles =
number of moles = 0.52 mol of iron
moles of chlorine gas
number of moles =
Substituting the values into the equation:
n = (molar mass of chlorine gas = 70.96 g/mol)
= 947.01 moles
As iron is the limiting reagent therefore
2 moles of Fe lead to 2 moles of FeCl3
0.52 moles of Fe will yield
=
0.52 moles of FeCl3 is produced.
To express this in grams:
mass = n x molar mass
= 0.52 x 162.2 (molar mass of FeCl3 is 162.2g/mol)
= 84.34 grams