Ask question

Ask question

All categories

4 months ago

6

The reaction between methanol and oxygen gas produces water vapor and carbon dioxide. 2CH3OH(l)+3O2(g)⟶4H2O(g)+2CO2(g) Three sea

led flasks contain different amounts of methanol and oxygen. Based on the molecular view of the three flasks, which would produce the largest quantity of total product? The flask contains 3 molecules of C H 3 O H and 3 molecules of O 2. The flask contains 1 molecule of C H 3 O H and 6 molecules of O 2. The flask contains 4 molecules of C H 3 O H and 2 molecule of O 2. For the flask which produces the largest quantity of total product, how many molecules of H2O will be formed? molecules of H2O :

1 answer:

Anarel [2.9K]4 months ago

6 0

Answer:

The flask yielding the greatest amount of product is the second flask.

The water molecules produced are $X = 8 \ molecules$

Explanation:

From the prompt we learn that

The chemical reaction is

2CH3OH(l) + 3O2(g)⟶4H2O(g)+2CO2(g)

The first flask contains 3 molecules of C H 3 O H and 3 molecules of O 2

The second flask has 1 molecule of C H 3 O H and 6 molecules of O 2.

The third flask consists of 4 molecules of C H 3 O H and 2 molecules of O 2.

Analyzing the three flasks, it's evident that the flask producing the most considerable total product is the second one.

According to the balanced equation, 2 moles of C H 3 O H react with 3 moles of oxygen, making O 2 the limiting reagent.

Generally, one mole of any substance is $1 * N_A$ of that substance.

Here, $N_A$ represents Avogadro's number valued at $N_A = 6.02214076 * 10^{23} \ molecules$ .

As seen in the balanced equation, 3 moles of O 2 (3 * $N_A$ molecules of O 2) yield 4 moles of H2O (4 *

Thus, 6 molecules of O 2 would generate X molecules of H 2 O.

So

$X = \frac{6 * (4 * N_A }{3 * N_A}$

=> $X = 8 \ molecules$

You might be interested in

In a certain compound of iron and oxygen, FexOy, it is found that a sample of this compound weighing 6.285 g contains 4.396 g of

castortr0y [3046]

Answer:

The oxide formula is $Fe_{2}O_{3}$

Explanation:

The provided compound contains iron (Fe) and oxygen (O).

Therefore, mass of oxygen in the sample = (total mass) - (mass of iron)

= (6.285 g) - (4.396 g)

= 1.889 g

Molar mass of oxygen = 16 g/mol and of iron = 55.845 g/mol.

Thus, the ratio of moles of Fe and O (Fe: O)

= $\frac{4.396}{55.845}:\frac{1.889}{16}$

= 0.0787: 0.118

= $1:\frac{0.118}{0.0787}$

= 1: 1.5

= 2: 3.

Consequently, the oxide formula is $Fe_{2}O_{3}$ .

5 0

3 months ago

A syringe contains 0.65 moles of he gas that occupy 900.0 ml. what volume (in l) of gas will the syringe hold if 0.35 moles of n

lions [2927]

<span>Using PV=nRT, which represents a universal constant for any state, we have: P1V1/n1T1=R and P2V2/n2T2=R; This implies that: P1V1/n1T1=P2V2/n2T2 Thus we can express it as V1/n1=V2/n2. Rearranging yields: V2=V1 x (n2/n1) = 750 mL x ((0.65+0.35)/(0.65)) = 1200 mL = 1.2 L... with 2 significant figures</span>

5 0

3 months ago

Read 2 more answers

Which of the following statements concerning hydrocarbons is/are correct?

Alekssandra [3086]

1. Saturated hydrocarbons can either be cyclic or acyclic structures. 2. An unsaturated hydrocarbon molecule contains at least one double bond. Explanation: Greetings, hydrocarbons are defined as the most basic organic compounds comprising only carbon and hydrogen. Therefore, we can eliminate the third statement since ethylenediamine is identified as an amine (an organic structure containing NH groups). Consequently, as saturated hydrocarbons only exhibit single bonds between carbons and carbon-hydrogens, they may be cyclic (ring-shaped) or acyclic (not ring-shaped), establishing the truth of the first statement. Finally, since saturated hydrocarbons exclusively feature single bonds while unsaturated hydrocarbons can exhibit double or triple bonds between carbons and carbon-hydrogens, the existence of at least one double bond categorizes the hydrocarbon as unsaturated. Hence, the first two statements are correct. Best regards.

6 0

2 months ago