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14 days ago

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Shaw’s carries two types of apple juice. One is 100% fruit juice, while the other is only 40% juice. Yesterday there was only on

e 48-ounce bottle of the 100% juice left. I bought it, along with a 32-ounce bottle of the 40% juice. I am about to mix the contents of the two bottles together. What percent of the mixture will be actual fruit juice?

1 answer:

Tems11 [2.7K]14 days ago

8 0

Response:

the proportion of genuine fruit juice in the combination will equal 76%

Clarification:

considering we're blending two bottles, the total volume of the blend will be

total volume = volume of bottle 1 + volume of bottle 2 = 48 ounces + 32 ounces = 80 ounces

furthermore, the overall juice content will be

juice content in the mixture = juice from bottle 1 + juice from bottle 2 = 48 ounces * 1 + 32 ounces * 0.4 = 60.8 ounces of juice

thus, the juice concentration in the mixture will be

concentration = 60.8 ounces of juice / 80 ounces = 0.76 (76%)

therefore, the percentage of true fruit juice in the blend will be 76%

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Explanation:

The provided cell reaction is:

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The half-reactions are:

Anode oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-$

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Utilizing the Nernst equation:

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T = room temperature = $25^oC=273+25=298K$

n = electrons exchanged in oxidation-reduction = 2

$E^o_{cell}$ = standard electrode potential for the cell = +0.63 V

$E_{cell}$ = cell potential for the reaction =?

$[Zn^{2+}]$ = concentration of Zn²⁺ = 3.5 M

$[Pb^{2+}]$ = $2.0\times 10^{-4}M$

Now substituting all known values into the equation, we arrive at:

$E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}$

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Answer:

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Explanation:

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According to this law, the mass of reactants must equal the mass of products, achievable through balancing the equation.
The application of coefficients 2, 3, 4, 4, 4 allows for an equal balance in the equation.
Consequently, the balanced equation can be written as:

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