The radius of the moon's orbit is calculated as R = 7.715 x 10⁷ m, and the moon's orbital period is T = 14.48 hr. The given orbital speed of the moon is v = 9.3 x 10³ m/s, with Neptune's mass being M = 1.0 x 10²⁶ Kg. The moon's orbital velocity can be expressed using the formula. Therefore, by squaring the equation and resolving for r + h, we calculate: R = GM / v². Upon substituting in, we find R to be 7.715 x 10⁷ m. The relation for the moon's orbital period yields T = 2π/ω and simplistically, T = 2πR/v, where ω = v/r. Following this, we compute T, leading to the conclusion: T = 14.48 hr.
B = µo*N*I/2r
Thus, B = 4πx10^-7*150*1.6/2*3.5 = 4.31x10^-5T
Response:
To find power, we must first determine the work done by the force.
1) We will use the following equation to calculate work:

The force is provided by the problem; our goal is to express 'dx' in terms of 't'
2) It's known that:

Thus, we have:

Then:

3) Finally, substituting all known values gives us:

After some calculations, the resulting work is:
161.9638 J.
4) To find power, we will use the following equation:

Thus
P = 161.9638/4.7 = 34.46 W