Answer:
The enthalpy of the second intermediate equation is altered by halving its value and changing the sign.
Explanation:
Let's examine both the first and second intermediate reactions alongside the overall equation concerning the examined process;
First reaction;
Ca (s) + CO₂ (g) + ½O₂ (g) → CaCO₃ (s) ΔH₁ = -812.8 kJ
Second reaction;
2Ca (s) + O₂ (g) → 2CaO (s) ΔH₂ = -1269 kJ
Thus, the overall reaction becomes;
CaO (s) + CO₂ (g) → CaCO₃ (s) ΔH =?
According to Hess's law, which states that the total heat change in a reaction is equal to the sum of the heat changes for each step, we cannot simply sum the enthalpies for this overall reaction. Instead, we obtain the overall enthalpy by halving the second intermediate reaction's enthalpy and changing its sign before adding, as illustrated below;
Enthalpy of Intermediate reaction 1 + ½(-Enthalpy of Intermediate reaction 2) = Enthalpy of Overall reaction
I predict that there will be an increase in the seconds recorded in the time column. This is because, as more water is mixed with sodium thiosulfate, its concentration diminishes in each flask. Additionally, a lower concentration results in a slower reaction rate since fewer molecules of sodium thiosulfate means there are less frequent collisions with sulfuric acid. With fewer collisions occurring in the reaction, it takes a longer time for the reaction to complete, leading to increased time when sodium thiosulfate is diluted.
Explanation:
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Answer:
The temperature of a vessel at a pressure reading of 1.250 atm is 296.43 K.
Explanation:
At standard temperature and pressure (STP), the temperature is valued at 273.15 K with a pressure of 1.000 atm.
If the pressure is measured as 1.250 atm at temperature T.


Applying Gay Lussac's law:
(When volume is constant)


At a pressure of 1.250 atm, the temperature of the vessel is 296.43 K.
Answer:
Explanation:
1) Alkali metals and halogens both need to achieve a stable outer electron shell, requiring alkali metals to lose one electron and halogens to gain one.
2) They share an identical count of outer shell electrons.
3) Typically, they have elevated melting points.
4) They exhibit low reactivity or none at all.
5) They belong to group 7.