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dusya
2 months ago
3

During an all-night cram session, a student heats up a one-half liter (0.50 x 10- 3 m3) glass (Pyrex) beaker of cold coffee. Ini

tially, the temperature is 18 °C, and the beaker is filled to the brim. A short time later when the student returns, the temperature has risen to 92 °C. The coefficient of volume expansion of coffee is the same as that of water. How much coffee (in cubic meters) has spilled out of the beak?
Physics
1 answer:
serg [3.5K]2 months ago
8 0

Answer:

ΔV_{c} = 7.415 10⁻⁶ m³   (7.415 10⁻³ L)

Explanation:

This problem seeks to calculate the change in volume of coffee and pyrex with the expression

                 ΔV = V₀ β ΔT

The coefficients for expansion are

Water Volumetry        β = 207 10⁻⁶ C⁻¹

Pyrex Linear                α = 3.2 10⁻⁶ C⁻¹

In general, for solids, the linear expansion coefficients are cited, but the volumetric coefficient is linked to

                  β = 3 α

Now, let’s compute the volume change for pyrex glass

                ΔV_{p} = V₀ 3α ΔT

                 ΔV_{p}= 0.50 10⁻³ 3 3.2 10⁻⁶ (92-18)

                ΔV_{p} = 3.552 10⁻⁷ m³

For the change in volume of coffee, which is equivalent to that of water

                ΔV_{w} = 0.50 10⁻³ 210 10⁻⁶ (92-18)

                ΔV_{w} = 7.77 10⁻⁶ m³

The spilled coffee amount represents the difference in the respective volumes

              ΔV_{c} =  ΔV_{w} -  ΔV_{p}

             ΔV_{c} = 7.77 10⁻⁶ - 3.552 10⁻⁷

              ΔV_{c} = 7.415 10⁻⁶ m³

To convert to liters

            ΔV_{c} = 7.415 10⁻⁶ m³ (1000 L / 1 m³)

             ΔV_{c} = 7.415 10⁻³ L

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Answer:

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Explanation:

Mass; m = 50 kg

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From the formula:

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Also, using the formula;

mg = GMm/r²

hence; g = GM/r²

Rearranging gives;

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r = √(6.67 × 10^(-11) × 50/11.08)

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8 0
1 month ago
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Softa [3030]

Answer:

1/7 kg

Explanation:

Refer to the attached diagram for enhanced clarity regarding the question.

One of the blocks weighs 1.0 kg and accelerates downward at 3/4g.

g denotes the acceleration due to gravity.

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Given M = 1.0 kg and a = 3/4g.

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Combining equations 1 and 2 gives;

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Substituting M = 1.0 kg and a = 3/4g into this equation leads to;

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3/4 g-g = -m(7/4 g)

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1 month ago
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According to Newton's third law of motion:

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In the scenario provided, Albert is pressing the book against the wall and subsequently decreases the force applied against the wall.

Let's evaluate all forces influencing the book in this situation.

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3. Albert’s force exerted on the book against the wall (x-axis)

4. Normal force of the wall reacting to Albert’s applied force (x-axis)

As Albert eases off his force, the new scenario reads:

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Since neither mass nor gravitational acceleration has changed, the weight exerted on the book remains the same.

2. As Albert reduces his force, the wall’s normal reaction force decreases correspondingly, following Newton's third law of motion.

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Ostrovityanka [3204]

Answer:

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7 0
1 month ago
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