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Ugo
17 days ago
5

You find a yellow rock and wonder if it is gold. how could you apply the scientific method to this problem

Physics
2 answers:
Maru [3.3K]17 days ago
8 0

In response to the given question, the scientific method is employed to analyze and clarify various natural occurrences.  

This method comprises several steps that include making observations, forming a scientific inquiry, conducting background research, proposing a hypothesis, running experiments, gathering data, analyzing results, and drawing conclusions in that order.

For the question at hand, the scientific method will similarly be utilized by researching background information, predicting and putting forth a hypothesis, along with conducting experiments to substantiate or refute the hypothesis. The data collected will then be assessed, leading to conclusions that will determine if the yellow rock is gold or not.

kicyunya [3.2K]17 days ago
6 0
To explore whether the yellow rock is gold, you should formulate a hypothesis grounded in established knowledge about gold and design an experiment to verify that hypothesis. For instance, since the density of gold is well established, your hypothesis could propose that if the rock is indeed gold, the water displacement in a container could be predicted from the rock's weight.

The procedure involves:

1. Investigating existing knowledge related to your inquiry (here, gold).
2. Creating a hypothesis that enables you to make forecasts based on that data.
3. Crafting an experiment to evaluate your predictions.
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A venturi is constructed of a 10.0 cm pipe with a 2.0 cm diameter throat. Water pressure in the pipe is twice atmospheric pressu
Ostrovityanka [3204]

Response:

P_t=5066250.0696\ Pa=50\ atm

Clarification:

Provided:

  • diameter of the pipe, d=0.1\ m
  • the throat's diameter, d_t=0.02\ m
  • flow velocity, v=0.4\ m.s^{-1}

The pressure in the pipe is twice the atmospheric pressure:

P=2\times 101325=202650\ Pa

To find the water's flow force:

F=P\times A

we now calculate the cross-sectional area of the pipe:

A=\frac{\pi.d^2}{4}

A=\pi \times\frac{0.1}{4}

A=0.007854\ m^2

Thus,

F=202650\times 0.007854

F=1591.6094\ N

Next, we determine the area at the throat:

A_t=\frac{\pi.d_t^2}{4}

A_t=\frac{\pi\times 0.02^2}{4}

A_t=0.000314\ m^2

So, the pressure at the throat becomes:

P_t=\frac{F}{A_t}

P_t=\frac{1591.6094}{0.000314}

P_t=5066250.0696\ Pa=50\ atm

6 0
20 days ago
Early investigators (including Thomas Young) measured the thickness of wool fibers using diffraction. One early instrument used
ValentinkaMS [3465]

Answer:

w= 1.867\times10^{-2}

Explanation:

Provided:

fiber diameter d= 18 μm

screen distance D= 30 cm

wavelength λ= 560 nm

from this, we can determine the fringe width

w=\frac{2\lambda D}{d}

substituting the values yield

w=\frac{2\times560\times10^{-9}\times0.3}{18\times10^{-6}

w= 1.867\times10^{-2}

8 0
1 month ago
Determine the sign (+ or −) of the torque about the elbow caused by the biceps, τbiceps, the sign of the weight of the forearm,
Sav [3153]
1. τbiceps = +(Positive) 2. τforearm = -(Negative) 3. τball = -(Negative) Explanation: The attached figure illustrates the following: 1. For the biceps, τbiceps indicates that torque is calculated as Torque = r x F, where r and F are vectors. Here, r corresponds to the vector from the elbow to the biceps. In the figure, the force from the biceps is directed upwards. Applying the right-hand rule from r to F results in counterclockwise torque, which is considered positive (+). 2. The torque related to the weight of the forearm, τforearm, uses the same torque formula, with r being the vector from the elbow to the forearm. The weight acts downward, causing a clockwise torque that is negative (-). 3. Similarly, for the weight of the ball, τball, the downward force from the ball's weight generates a clockwise torque, which also registers as negative (-).
8 0
21 day ago
1)After catching the ball, Sarah throws it back to Julie. However, Sarah throws it too hard so it is over Julie's head when it r
Softa [3030]

Answer:

1)

v_{oy}=11.29\ m/s

2)

y=7.39\ m

Explanation:

Projectile Motion

When an object is projected near the surface of the Earth at an angle \theta to the horizontal, it follows a trajectory known as a parabola. The only force acting on it (ignoring wind resistance) is gravity, affecting the vertical axis.

The height of a projectile can be calculated using

\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}

where y_o represents the initial height from ground level, v_{oy} is the vertical component of the initial velocity, and t is the elapsed time.

The vertical speed component is expressed as

v_y=v_{oy}-gt

1) To proceed, we will determine the initial vertical velocity component since we lack sufficient data to calculate the absolute value of v_o.

The peak height is attained when v_y=0, which allows us to compute the time to reach that height.

v_{oy}-gt_m=0

Solving for t_m

\displaystyle t_m=\frac{v_{oy}}{g}

Thus, the maximum height reached is

\displaystyle y_m=y_o+\frac{v_{oy}^2}{2g}

We know this value is equal to 8 meters

\displaystyle y_o+\frac{v_{oy}^2}{2g}=8

Continuing with the calculations for v_{oy}

\displaystyle v_{oy}=\sqrt{2g(8-y_o)}

Substituting known values yields

\displaystyle v_{oy}=\sqrt{2(9.8)(8-1.5)}

\displaystyle v_{oy}=11.29\ m/s

2) At t=1.505 seconds, the ball is positioned above Julie’s head; we can calculate

\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}

\displaystyle y=1.5+(11.29)(1.505)-\frac{9.8(1.505)^2}{2}

\displaystyle y=1.5\ m+16,991\ m-11.098\ m

y=7.39\ m

5 0
2 months ago
Use the formula t = (0.25) s1/2 to find the time t in seconds it will take a stone to drop a distance s of 200 feet. Round your
inna [3103]

Answer:

The duration, t = 3.53 seconds

Explanation:

The following information is provided:

The equation to calculate the time t is expressed as:

t=(0.25)s^{1/2}...... (1)

Where

s denotes the distance in feet

We are to determine the duration taken by the stone to fall a distance of 200 feet, where s = 200 feet

Substituting the value of s into equation (1) yields:

t=(0.25)\times (200)^{1/2}

t = 3.53 seconds

Thus, the time taken by the object is 3.53 seconds, which provides the required answer.

4 0
1 month ago
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