Answer:
Explanation:
a) La fuerza neta que actúa sobre la caja en la dirección vertical es:
Fnet=Fg−f−Fp *sin45 °
aquí Fg representa la fuerza gravitacional, f es la fuerza de fricción, y Fp es la fuerza de empuje.
Fnet=ma
ma=Fg−f−Fp *sin45 °
a=
=0.24 m/s²
Vf =Vi +at
=0.48+0.24*2
Vf=2.98 m/s
b)
Fnet=Fg−f−Fp *sin45 °
=Fg−0.516Fp−Fp *sin45 °
=30-1.273Fp
Fnet=0 (Ya que la velocidad es constante)
Fp=30/1.273
=23.56 N
The result is 70.5 km/h. It seems the question is somewhat vague, but you're inquiring about the x-component of the helicopter's velocity. The x and y components can be calculated using sine and cosine ratios. The sine ratio connects the y-component with the overall velocity as follows: sin(angle) = y-component of velocity / velocity. Meanwhile, the cosine ratio relates the x-component to the velocity: cos(angle) = x-component of velocity / velocity. Given that you have both the angle and the velocity, and need to determine the x-component, you should apply the cosine ratio: cos(35°) = x-component / 86.0 km/h => x-component = 86.0 km/h * cos(35°) = 70.5 km/h.
A reactant is any substance that takes part in a chemical reaction. Conversely, a product is what emerges from the chemical transformation. A familiar example of a chemical change is rust formation. In this reaction, oxygen and iron, which serve as the reactants, react to produce a substance known as iron oxide, or rust.
Answer:
b. The loop's current consistently flows in a counterclockwise direction.
Explanation:
As a magnet descends through a wire loop, it generates an induced current within that loop. This induced current arises due to the magnet's movement, leading to a variation in magnetic flux. Lenz's law states that the induced current will act to counteract the change that produces it. In this scenario, the only feasible resistance to the magnet’s fall is through inducing a similar pole on the loop to counteract its downward motion. An induced current that circulates counterclockwise in the wire loop mimics the polarity of a northern pole, thereby repelling the magnet's descent. Furthermore, as the magnet passes the wire loop, this induced north pole will seek to attract the magnet's south end in an effort to halt its downward progression.
