A pressure cooker cooks a lot faster than an ordinary pan by maintaining a higher pressure and temperature inside. the lid of a

The charge for a single electron is 1.602*10^ -19 C

80 µC can be expressed as 8*10^ - 5 C

This is basic arithmetic

Total Charge divided by the charge of one electron = Number of electrons

(8*10^ -5 C / 1.602*10^ -19 C) equals 4.99 * 10^14 electrons.

The force due to electricity on the charge is calculated by multiplying the charge by the intensity of the electric field:

in our scenario, where and , resulting in the force of


Initially, the kinetic energy of the particle is at zero (as it remains stationary), which means its final kinetic energy is equal to the work performed by the electric force over a distance of x=4 m:

The mass, m, of the gas amounts to 0.2504 grams. Explanation: First, we need to calculate the cylindrical tube's volume. The formula for the volume of a cylinder is given by; where V indicates volume, π signifies pi, r represents the radius, and h indicates height or length. Given the following parameters: Radius, r = 1.5 cm, Length, h = 14.4 cm, Density, d = 0.00123 g/cm³. Plugging these into the equation, the volume of the cylindrical tube calculates to be 203.6016 cm³. Density can be defined as mass divided by the volume of an object. Simply put, density is mass per unit volume. Mathematically, density is represented by the formula; by substituting into the equation, we conclude that Mass = 0.2504 g.

When helium is released from a compressed container, the decompressed atoms expand and rise, causing the rubber balloon to inflate and float along. In this scenario, helium exists in a gaseous state.

Answer:   1m, 1m, 2m, 2m, 4m, 4m.

It’s important to remember that the masses attached do not influence the number of oscillations.

Explanation:

To determine the number of oscillations (complete cycles), we can apply the formula n = t / T ……equation 1

The variables that impact the period of a simple pendulum are solely its length and gravitational acceleration. The period remains unaffected by factors such as mass.

period (T)= 2 x π x √(L/g) ….equation 2

where π = 3.142, L= rope length, and g = 9.8 m/s (gravitational acceleration)

According to the question, the time (t) is 60 seconds.

By merging equations 1 and 2, we obtain  

number of oscillations = time / (2 x π x √(L/g))

Case 1: for L = 4m

number of oscillations = 60 / ( 2 x 3.142 x √(4/9.8))

= 14.9 = 14 complete cycles (the problem specifies complete cycles)

Case 2: for L = 2m

number of oscillations = 60 / ( 2 x 3.142 x √(2/9.8))

= 21.4 = 21 complete cycles

Case 3: where L = 4m, results in the same as case 1, yielding 14 complete cycles

Case 4: where L = 2m, mirrors the outcome in case 2, producing 21 complete cycles

Case 5: in the instance of L = 1m

number of oscillations = 60 / ( 2 x 3.142 x √(1/9.8))

= 30.1 = 30 complete cycles

Case 6: when L = 1m, which repeats case 5, also gives 30 complete cycles

From these findings, the order of the pendulums from the highest to lowest number of complete cycles is as follows: 1m, 2m, 2m, 4m, 4m.

Remember, the number of oscillations is independent of their respective masses.