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7nadin3
23 days ago
13

A baby elephant is stuck in a mud hole. to help pull it out, game keepers use a rope to apply a force f with arrowa, as part a o

f the drawing shows. by itself, however, force f with arrowa is insufficient. therefore, two additional forces f with arrowb and f with arrowc are applied, as in part b of the drawing. each of these additional forces has the same magnitude f. the magnitude of the resultant force acting on the elephant in part b of the drawing is k times larger than that in part
a. find the ratio f fa when k = 2.10. (take θ = 18.0°.) f fa = 1.05 incorrect: your answer is incorrect.
Physics
1 answer:
Maru [2.3K]23 days ago
3 0

The two forces must balance, therefore:

2.10 * Fa = Fa + 2 * F * cos 18

When simplifying the right-hand side:

2.10 * Fa = Fa + 1.902 * F

1.10 Fa = 1.902 F

<span>F / Fa = 0.578</span>

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mass₃<mass₁=mass₅<mass₂=mass₄

Explanation:

Data points:-

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2. mass: 4 m   speed: v

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4. mass: 4 m   speed: v

5. mass: 4 m   speed: ½ v

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Where m represents the mass of the object

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<psubstituting the="" given="" values="" for="" mass="" and="" speed="" from="" previous="" data:="">

The KE of Body 1(mass₁) = ½*m*v²             = mv²/2

KE of Body 2(mass₂) = ½*4m*v²         = 2mv²

KE of Body 3(mass₃) = ½*2m*(1/4v)²  =  mv²/16

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Explanation:

Refer to the attached diagram for enhanced clarity regarding the question.

One of the blocks weighs 1.0 kg and accelerates downward at 3/4g.

g denotes the acceleration due to gravity.

Let M represent the block with known mass, while 'm' signifies the mass of the other block and 'a' refers to the acceleration of body M.

Given M = 1.0 kg and a = 3/4g.

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