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Vinil7
16 days ago
6

1. A student sees tiny bubbles clinging to the inside of an unopened plastic bottle full of carbonated soft drinks. The student

squeezes the bottle.
a. The bubbles will shrink, and some may vanish.
b. The bubbles will grow, and more may appear.
c. The bubbles won't change.
2. A student has two unopened 33cL cans containing carbonated water. Can A has been stored in the garage (32°C) and can B has been stored in the fridge (8°C). The student opens one can at the time, both cans make a fizz.
a. Can A will make a louder and stronger fizz than can B.
b. Can B will make a louder and stronger fizz than can A.
c. The fizz will be the same for both cans.
d. There is not enough information to predict which can will make the louder fizz.
Chemistry
1 answer:
Alekssandra [2.8K]16 days ago
3 0

Response:

1) The bubbles will expand, and additional ones might surface.

2) Can A will produce a more intense and resonant fizz than Can B.

Explanation:

By compressing the bottle's sides, the pressure exerted increases on the bubbles, forcing them into a smaller area. This reduction in volume results in an increased density of the bubble. When density rises, the bubble enlarges and new bubbles can form. Consequently, altering the pressure (by squeezing the bottle) modifies the bubble sizes while retaining the number of bubbles. In carbonated beverages, higher temperatures cause a quicker loss of fizz due to the increased volatility of carbon dioxide in liquids at elevated temperatures. This principle explains that carbon dioxide's solubility in can A at 32°C is lower than in can B at 8°C, making can A's fizz louder compared to can B's.

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According to the law of conservation of mass, if an element A has an atomic mass of 2 mass units and element B has an atomic mas
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The principle of conservation of mass asserts that mass cannot be created or eliminated. Given that element A has a mass of 2 g/mol and element B has a mass of 3 g/mol, the total mass of compound AB equals the combined molar masses: 2 g/mol + 3 g/mol results in 5 g/mol for AB. As for A2B3, the calculation is as follows: A2 has 2 multiplied by 2, yielding 4 g/mol, while B3 equals 3 multiplied by 3, which gives 9 g/mol. Consequently, A2B3 amounts to 13 g/mol.
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1 month ago
Select the correct answer from each drop-down menu.
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The direction of the arrow indicates that the bond involving the chlorine atom and the fluorine atom is nonpolar. The fluorine atom pulls the electrons in the bond with greater strength, resulting in the chlorine atom being a little positive.

Explanation:

  • The bond formed between chlorine and fluorine displays nonpolar characteristics because both atoms contribute an equal share of electrons within the bond. Examples such as H2, F2, and Cl2 illustrate this concept well.
  • Both chlorine and fluorine are electronegative elements, yet fluorine resides above chlorine in the periodic table. Fluorine's position above chlorine gives it a somewhat higher electronegativity compared to chlorine. This explains why fluorine molecules attract electrons more efficiently than chlorine atoms, resulting in chlorine exhibiting a slight positive charge in bonds between Cl and F.

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25 days ago
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The final overall chemical equation is Upper Ca upper O (s) plus upper C upper O subscript 2 (g) right arrow upper C a upper C u
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Answer:

The enthalpy of the second intermediate equation is altered by halving its value and changing the sign.

Explanation:

Let's examine both the first and second intermediate reactions alongside the overall equation concerning the examined process;

First reaction;

Ca (s) + CO₂ (g) + ½O₂ (g) → CaCO₃ (s) ΔH₁ = -812.8 kJ

Second reaction;

2Ca (s) + O₂ (g) → 2CaO (s) ΔH₂ = -1269 kJ

Thus, the overall reaction becomes;

CaO (s) + CO₂ (g) → CaCO₃ (s) ΔH =?

According to Hess's law, which states that the total heat change in a reaction is equal to the sum of the heat changes for each step, we cannot simply sum the enthalpies for this overall reaction. Instead, we obtain the overall enthalpy by halving the second intermediate reaction's enthalpy and changing its sign before adding, as illustrated below;

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7 0
1 month ago
A 20.0–milliliter sample of 0.200–molar K2CO3 so­lution is added to 30.0 milliliters of 0.400–mo­lar Ba(NO3)2 solution. Barium c
KiRa [2857]

Respuesta:

0.16 M

Explicación:

Teniendo en cuenta:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

O sea,

Moles =Molarity \times {Volume\ of\ the\ solution}

Dado que:

Para K_2CO_3 :

Molaridad = 0.200 M

Volumen = 20.0 mL

Convierte mL a L:

1 mL = 10⁻³ L

Entonces, volumen = 20.0×10⁻³ L

Los moles de K_2CO_3 son:

Moles=0.200 \times {20.0\times 10^{-3}}\ moles

Moles de K_2CO_3 = 0.004 moles

Para Ba(NO_3)_2 :

Molaridad = 0.400 M

Volumen = 30.0 mL

Convertimos mL a L:

1 mL = 10⁻³ L

Volumen = 30.0×10⁻³ L

Entonces, los moles de Ba(NO_3)_2 son:

Moles=0.400 \times {30.0\times 10^{-3}}\ moles

Moles de Ba(NO_3)_2 = 0.012 moles

Según la reacción:

Ba(NO_3)_2 + K_2CO_3\rightarrow BaCO_3 + 2KNO_3

1 mol de Ba(NO_3)_2 reacciona con 1 mol de K_2CO_3

Por lo tanto,

0.012 mol de Ba(NO_3)_2 reacciona con 0.012 mol de K_2CO_3

Moles disponibles de K_2CO_3 = 0.004 mol

El reactivo limitante es el que está en menor cantidad, entonces K_2CO_3 es el limitante (0.004 < 0.012).

La formación del producto depende del reactivo limitante, así que,

1 mol de K_2CO_3 reacciona con 1 mol de Ba(NO_3)_2 y produce 1 mol de BaCO_3

0.004 mol de K_2CO_3 reacciona con 0.004 mol de Ba(NO_3)_2 y genera 0.004 mol de BaCO_3

Los moles restantes de Ba(NO_3)_2 son: 0.012 - 0.004 = 0.008 mol

El volumen total es 20 + 30 mL = 50 mL = 0.050 L

Por lo que la concentración del ion bario, Ba^{2+}, después de la reacción es:

Molarity=\frac{0.008}{0.050}\ M = 0.16\ M

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Yasir wished to explore how sleep relates to room color. He conducted necessary preliminary research and formed a hypothesis suggesting individuals doze off faster in blue-painted rooms compared to those painted in yellow. Yasir surveyed several individuals about their color preference—yellow or blue—and utilized their feedback to assess the validity of his hypothesis. However, he did not conduct an actual experiment to examine the impact of room color on sleep, and he failed to clearly define the variables that should have been part of his experiment.

Hence, the correct answer would be,

An experiment that directly tests the hypothesis

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1 month ago
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